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zhuklara [117]
3 years ago
13

Expressions, Equations & inequalities Question 1Solve the inequality12x + 151 - 19​

Mathematics
2 answers:
Setler [38]3 years ago
7 0

Answer:

12x + 151 - 19

12x + 132

12 (x + 11)

aliya0001 [1]3 years ago
3 0

Answer:

I believe the answer is 12 • (x + 11) .

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Use trigonometric ratios to find the indicated side
iragen [17]

Answer:

a = 139.1

b = 56.2

Step-by-step explanation:

A. Reference angle = 68°

Opp = a

Hyp = 150

Therefore:

Sin 68 = opp/hyp

Sin 68 = a/150

150*sin 68 = a

a = 139.1 (nearest tenth)

B. Reference angle = 68°

Adj = b

Hyp = 150

Therefore:

Cos 68 = adj/hyp

Cos 68 = b/150

150*cos 68 = b

b = 56.2 (nearest tenth)

4 0
2 years ago
Gaming a video-game designer is using the expression 6n3 in a program to determine points earned, where n is the game level. sim
charle [14.2K]

Gaming a video-game designer is using the expression 6n3 in a program to determine points earned, where n is the game level.

Given expression is 6n^3. the given expression is for the nth level.

To simplify the expression for the  n^2 level, we plug in n^2  in the place of 'n' in the given expression

6n^3

6(n^2)^3 (multiply the exponents)

6n^6


5 0
3 years ago
Read 2 more answers
PLEASE HELPPPP ILL MARK BRAINLIEST
NNADVOKAT [17]
Coordinate 1 is : (0,3)
Coordinate 2 is : (-4,-2)
Coordinate 3 is : (-1,-5)
Coordinate 4 is (4,0)
Hope this helps!
7 0
2 years ago
Which expression is equivalent to (16 x Superscript 8 Baseline y Superscript negative 12 Baseline) Superscript one-half?.
loris [4]

To solve the problem we must know the Basic Rules of Exponentiation.

<h2>Basic Rules of Exponentiation</h2>
  • x^ax^b = x^{(a+b)}
  • \dfrac{x^a}{x^b} = x^{(a-b)}
  • (a^a)^b =x^{(a\times b)}
  • (xy)^a = x^ay^a
  • x^{\frac{3}{4}} = \sqrt[4]{x^3}= (\sqrt[3]{x})^4

The solution of the expression is \dfrac{4x^4}{y^6}.

<h2>Explanation</h2>

Given to us

  • (16x^8y^{12})^{\frac{1}{2}}

Solution

We know that 16 can be reduced to 2^4,

=(2^4x^8y^{12})^{\frac{1}{2}}

Using identity (xy)^a = x^ay^a,

=(2^4)^{\frac{1}{2}}(x^8)^{\frac{1}{2}}(y^{12})^{\frac{1}{2}}

Using identity (a^a)^b =x^{(a\times b)},

=(2^{4\times \frac{1}{2}})\ (x^{8\times\frac{1}{2}})\ (y^{12\times{\frac{1}{2}}})

Solving further

=2^2x^4y^{-6}

Using identity \dfrac{x^a}{x^b} = x^{(a-b)},

=\dfrac{2^2x^4}{y^6}

=\dfrac{4x^4}{y^6}

Hence, the solution of the expression is \dfrac{4x^4}{y^6}.

Learn more about Exponentiation:

brainly.com/question/2193820

8 0
2 years ago
Which of the following expressions is equivalent to the expression x - (-3) ?
kolezko [41]
X + 3 because in math two negatives equal a positive
6 0
3 years ago
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