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Yuri [45]
3 years ago
6

Pls help me I’ll give brainliest!

Mathematics
1 answer:
PtichkaEL [24]3 years ago
8 0

Answer:

18750

Step-by-step explanation:

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jasenka [17]

Answer:

-200

Step-by-step explanation:

7 0
3 years ago
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Solve for x<br> 1 7 1<br> 2<br> х<br> Your answer
ki77a [65]

Answer:

x = 4

Step-by-step explanation:

3x -5 = -2 + 9

-2 + 9 = 7 so now its 3x - 5 = 7

add 5 to the -5 so it cancels itself out. then add the 5 to 7 so it become 12. the you have 3x = 12

divide 12 ÷ 3 = 4

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8 0
3 years ago
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Help i’ll give brainliest
mash [69]

Answer:

It will cost $36.38 to travel 8.9 miles.

Step-by-step explanation:

In order to get how much it will cost to travel 8.9 miles, you need to first set up a linear equation (in slope-intercept form, which is y=mx+b ). You can do this with what the problem has given us. Since there's a flat fee of $3, that is the y-intercept or the b slope-intercept form. Then there is $3.75 added for every additional mile traveled, making it the slope or the m in slope-intercept form. That makes the equation look like:

y=3.75x+3

The x in that equation represents how far you traveled. Therefore in order to find out 8.9 miles, plug in 8.9 for x.

y=3.75(8.9)+3

Simply solve the equation and you will have how much it will cost to travel 8.9 miles.

y=33.375+3

Now add the like terms:

y=36.375

Since it needs to be rounded to the nearest cent, you will round to the nearest tenth:

y=36.38

Therefore, it will cost $36.38 to travel 8.9 miles.

6 0
3 years ago
Ms. Marigneaux's science class needs to
sertanlavr [38]

If there are 29 students in class and they need to collect a total of 168, we can divide 168 by 29 to get $5.79. This means that each student must collect $5.79 in order for them to be able to purchase everything.

6 0
4 years ago
Are the forces blanched or unbalanced support your answer :)
s2008m [1.1K]

 there is 100 pushing to the right and 10 pushing to the left 
 since 100 is larger than 10, the force is unbalanced.and the object would move to the right.
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3 years ago
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