Answer:
The total area of a prism is
![A=ph +2B](https://tex.z-dn.net/?f=A%3Dph%20%2B2B)
Where
is the perimeter of the base,
is the height of the prims and
is the area of the base.
Remember that the perimeter is the sum of all side. So, first we need to find the hypothenuse of the base triangle.
![h^{2}=4^{2} +6^{2}\\ h=\sqrt{16+36} =\sqrt{52} \approx 7.2](https://tex.z-dn.net/?f=h%5E%7B2%7D%3D4%5E%7B2%7D%20%20%2B6%5E%7B2%7D%5C%5C%20h%3D%5Csqrt%7B16%2B36%7D%20%3D%5Csqrt%7B52%7D%20%5Capprox%20%207.2)
Now, the perimeter of the base is
![p=7.2+6+4=17.2](https://tex.z-dn.net/?f=p%3D7.2%2B6%2B4%3D17.2)
Also, the height of the prism is
, and the area of the base is
![B=\frac{1}{2}4(6)=12](https://tex.z-dn.net/?f=B%3D%5Cfrac%7B1%7D%7B2%7D4%286%29%3D12)
Then, we replace all values,
![A=17.2(8)+2(12)=137.6+24=161.6](https://tex.z-dn.net/?f=A%3D17.2%288%29%2B2%2812%29%3D137.6%2B24%3D161.6)
So, the total area of the prism is 161.6 square units, approximately.
Now, the lateral area is defined as
, replacing all values, we have
![L=17.2(8)=137.6](https://tex.z-dn.net/?f=L%3D17.2%288%29%3D137.6)
So, the lateral area is 137.6 square units, approximately.