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3 years ago

Consider the hypothesis test below.

Mathematics

1 answer:

Pavel [41]3 years ago

8 0

Answer:

$Z_{H0} =1.79$

p-value: 0.0367

Decision: Reject H₀

Step-by-step explanation:

Hello!

Hypothesis to test:

H₀:ρ₁-ρ₂=0

H₁:ρ₁-ρ₂>0

The statistic to use to test the difference between two population proportions is the approximation of Z

Z=<u> (^ρ₁-^ρ₂)-(ρ₁-ρ₂) </u> ≈N(0;1)

√ (<u>^ρ₁(1-^ρ₁))/n₁)+(^ρ₂(1-^ρ₂)/n₂))</u>

Z=<u> (0.28-0.15)-0 </u>= 1.79

√ (<u>0.28(1-0.28)/200)+(0.15(1-0.15)/300)</u>

p-value

Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

P(Z>1.79)= 0.0367

Conclusion:

Comparing the p-value against the significance level, you can decide to reject the null hypothesis.

I hope you have a SUPER day!

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Given the function f(x)=-5x^2+2x+9,find f(1) and f(2) Choose the statement that is true concerning these two values

SIZIF [17.4K]

F(1) = -5(1)^2+2(1)+9 = 6
f(2) = -5(2)^2+2(2)+9 = -9

So, because f(1) = 6 is positive and f(2) = -9 is negative, f(1) > f(2).

f(1) is greater than f(2)!

6 0

3 years ago

Read 2 more answers

Nine tiles are numbered $\color[rgb]{0.35,0.35,0.35}1, 2, 3, \ldots, 9$. Each of three players randomly selects and keeps three

Eduardwww [97]

The probability that all three players obtain an odd sum is 3/14.

<h3>What is probability?</h3>

The probability is the ratio of possible distributions to the total distributions.

I.e.,

Probability = (possible distributions)/(total distributions)

<h3>Calculation:</h3>

Given that,

There are nine tiles - 1, 2, 3,...9, respectively.

A player must have an odd number of odd tiles to get an odd sum. That means he can either have three odd tiles, or two even tiles and an odd tile.

In the given nine tiles the number of odd tiles = 5 and the number of even tiles = 4.

The only possibility is that one player gets 3 odd tiles and the other two players get 2 even tiles and 1 odd tile.

So,

One player can be selected in $^3C_1$ ways.

The 3 odd tiles out of 5 can be selected in $^5C_3$ ways.

The remaining 2 odd tiles can be selected and distributed in $^2C_1$ ways.

The remaining 4 even tiles can be equally distributed in $\frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !}$ ways.

So, the possible distributions = $^3C_1$ × $^5C_3$ × $^2C_1$ × $\frac{4 ! \cdot 2 !}{(2 !)^{2} \cdot 2 !}$

⇒ 3 × 10 × 2 × 6 = 360

To find the total distributions,

The first player needs 3 tiles from the 9 tiles in $^9C3=84$ ways

The second player needs 3 tiles from the remaining 6 tiles in $^6C_3=20$ ways

The third player takes the remaining tiles in 1 way.

So, the total distributions = 84 × 20 × 1 = 1680

Therefore, the required probability = (possible distributions)/(total distributions)

⇒ Probability = 360/1680 = 3/14.

So, the required probability for the three players to obtain an odd sum is 3/14.

Learn more about the probability of distributions here:

brainly.com/question/2500166

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1 year ago

WILL GIVE BRAINLIEST IF CORRECT, IF WRONG NO BRAINLIEST Which statement accurately explains whether a reflection over the x-axis

Paladinen [302]

9514 1404 393

Answer:

No, A″C″B″ is located at A″(1, 1), C″(4, 3), and B″(1, 5)

Step-by-step explanation:

Line AB is horizontal, so reflection across the x-axis maps it to a horizontal line. Then rotation CCW by 90° maps it to a vertical line. The composition of transformations cannot map the figure to itself.

A reasonable explanation is the last one:

No, A″C″B″ is located at A″(1, 1), C″(4, 3), and B″(1, 5)