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PSYCHO15rus [73]
4 years ago
11

Hi I wanted to know how to change my username.

Engineering
1 answer:
exis [7]4 years ago
4 0

Answer:

Click on your profile

Then click “view your profile”

Then click edit profile

Then change it to whatever you want

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A damped harmonic oscillator consists of a mass on a spring, with a damping force proportional to the speed of the block. If the
Murrr4er [49]

Answer:

TOTAL ENERGY = 0.74 j

Explanation:

Given data:

spring constant is 350 N/m

m = 0.24 kg

b = 0.41 kg/s

A = 0.075 M

\omega = \sqrt{\frac{k}{m}}

             = \sqrt{\frac{350}{0.24}}

y = e^{\frac{-b}{2m} t} A cos(\omega t)

  =e^{\frac{-0.41}{2*0.24} t} cos (\sqrt{\frac{350}{0.24}} t) *0.075

after one full cycle, mass will be at extreme point, hence K,E = 0

But total energy remain same

y after one full cycle is\

y =e^{\frac{-0.41}{2*0.24} 2\pi \sqrt{\frac{0.24}{350}}} cos (2\pi*0.075)

y = 0.06517 m

y = 6.517 cm

total energy = \frac{1}{2} k y^2

= \frac{1}{2}* 350* 0.06517^2 = 0.742 J

8 0
4 years ago
For laminar flow over a flat plate, the local heat transfer coefficient hx is known to vary as x−1/2, where x is the distance fr
Reika [66]

Answer:

2

Explanation:

So for solving this problem we need the local heat transfer coefficient at distance x,

h_x=cx^{-1/2}

We integrate between 0 to x for obtain the value of the coefficient, so\bar{h}_x =\frac{1}{x} \int\limit^x_0 h_x dx\\\bar{h}_x = \frac{c}{x} \int\limit^x_0 \frac{1}{\sqrt{x}}dx\\\bar{h}_x = \frac{c}{c} (2x^{1/2})\\\bar{h}_x = 2cx^{-1/2}

Substituing

\bar{h}_x=2h_x\\\frac{\bar{h}_x}{h_X}=2

The ratio of the average convection heat transfer coefficient over the entire length is 2

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Drawbacks include that it is costlier than other clean energies. Another thing is that when it isnt sunny you wont get as much energy

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Which of the following is a function of a safety device
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what are the options available?

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computer engineers

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mechanical engineers

manufacturing engineers

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