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3 years ago

HELP FOR POINTSS

Mathematics

2 answers:

Y_Kistochka [10]3 years ago

4 0

T(x)= 10c + 5p
T represents their target of $200
X represents the cakes or pies

brilliants [131]3 years ago

3 0

The answer would be
C = 10
P = 20

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In the electric currect flow, it is found that the resistance (measured in the units called ohms) offered by a fixed length o

Morgarella [4.7K]

Let x be the resistance of the wire with the larger diameter.
x = (0.456 x (0.01)^2)/(0.0401)^2 = 0.0284 ohms
The answer is 0.0284 ohms.

7 0

2 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

2 years ago

Who had this before if so can I get help

telo118 [61]

2*3+4=10

5+2x2=9

4-3+2=3

4*3+2=14

20-4x3+6=14

16-30/2+11=12

24/6*5=20

15/5+2=5

2+2*9-5=15

12-3+4*2=1

12/3+3*4=16

9-6/3=7

16-3*4=4

36/4/9=1

The last one is yours

6 0

2 years ago

F m 1=7x and m 4=3x+20 what is the m 2

djyliett [7]

M2=5x+10
.................

4 0

3 years ago

Hi! I know this is not the correct way to ask a question, but may someone explain how to do the Division Property of Equality an

soldier1979 [14.2K]

Answer:

Step-by-step explanation:

So the division property states that if both sides of an equation are equal and whenever you divide both sides of that equation by the same number they should stay equal. Example

12=12 right? so if I divide both 12 and 12 by 3 I should get 3=3

We use this to solve for variable such as x

So new example lets take

5x=25

Since both sides are equal I can divide by the same number and should get an equal number right? So lets divide by 5 on both sides. 5x divided by 5 equals x and 25 divided by 5 equals 5 so my new equation is

x equals 5 or x=5.

If I plug my x=5 back into the equation they should be equal so lets see...

5(5)=25

25=25

And it checks out :)

3 0

2 years ago