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amm1812
3 years ago
5

There are 420 students . The ratio from girls to boys is 4- 3 . How many more girls?

Mathematics
1 answer:
viktelen [127]3 years ago
6 0
There are 60 more girls
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What is the probability
vovikov84 [41]
Current price is $14.98.


$14.98/.50 = $29.96. This was the price after the 20% mark down. Now calculate the original as follows:


$29.96/.80 = $37.45. This is the original price before all the discounts.
8 0
3 years ago
Becky has 9 bags of coins. Some of the bags contain 8 gold coins, and the rest contain 6
fredd [130]

Answer:

4 bags of gold coins and 6 bags of gold coins

Step-by-step explanation:

So, Becky has 9 bags of coins

This is basically a "trial and error" equation.

Now, she has 4 bags of 8 gold coins

8×4= 32

So she has 32 gold coins

Now, she has 5 bags of 6 silver coins

5×6=30

So she has 30 silver coins.

So we add these,

30+32= 62

HOPE THIS HELPS!!!

7 0
3 years ago
My number is less than 50. - it is a factor of 70. - it is a multiple of 5 and 7. what is minnu's number? a. 5 b. 35 c. 14 d. 70
Nostrana [21]

Answer:

B) 35

Step-by-step explanation:

35 is less than 50 and it's a factor of 70, a multiple of 5 and 7 is 35 just by multiplying the numbers it will give you that answer.

6 0
2 years ago
What is wrong with the equation? 2 x−3 dx = x−2 −2 2 −3 = − 5 72 −3 f(x) = x−3 is continuous on the interval [−3, 2] so FTC2 can
Wewaii [24]

Answer:

Hello your question is incomplete below  is the complete question

What is wrong with the equation? integral^2 _3 x^-3 dx = x^-2/-2]^2 _3 = -5/72 f(x) = x^-3 is continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous on the interval [-3, 2] so FTC2 cannot be applied. f(x) = x^-3 is not continuous at x = -3, so FTC2 cannot be applied The lower limit is less than 0, so FTC2 cannot be applied. There is nothing wrong with the equation. If f(2) = 14, f' is continuous, and f'(x) dx = 15, what is the value of f(7)? F(7) =

answer : The value of f(7) = 29

Step-by-step explanation:

Attached below is the detailed solution

Hence : F(7) - 14 = 15

F(7) = 15 + 14 = 29

8 0
4 years ago
Lucas wants to use the box with the greatest volume
stiks02 [169]

*see attachment for the possible choice answers showing the boxes and dimensions

Answer:

Box D = 27 ft³

Step-by-step explanation:

To find out which has the greatest volume, we need to calculate the volume of each box given in the option using the formula of the volume of a rectangular prism = w × h × l.

Where w = width; h = height; and l = length.

Thus, the volume for the boxes are as follows:

=>Box A:

V = w × h × l

V = 3 × 1 × 5

V = 15 ft³

=>Box B:

V = w × h × l

V = 2 × 3 × 4

V = 24 ft³

=>Box C:

V = w × h × l

V = 1 × 2 × 7

V = 14 ft³

=>Box D:

V = w × h × l

V = 3 × 3× 3

V = 27 ft³

The shipping box with the largest volume is box D with a volume of 27 ft³

7 0
4 years ago
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