Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
First, you have to simplify the equation:
y+3 = 3(x+5)
y+3=3x+15
So you multiply what’s inside the brackets (x+5) by the factor (3). So 3•x=3x, 3•5=15.
Then you rearrange the equation as necessary to convert it into standard form, which is Ax + By = C
Answer:
The correct answer is 56
Step-by-step explanation:
Parallelogram PARL is similar to parallelogram WXYZ. If AP = 14, PL = 25, and WZ = 100, find the value of c.
100=25*4, so the other side must be also multiplicated by 4 ansd 14*4=56
