Not enough information to properly answer this... hope this helped though
Answer:
the second one
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given that a professor sets a standard examination at the end of each semester for all sections of a course. The variance of the scores on this test is typically very close to 300.

(Two tailed test for variance )
Sample variance =480
We can use chi square test for testing of hypothesis
Test statistic = 
p value = 0.0100
Since p <0.05 our significance level, we reject H0.
The sample variance cannot be claimed as equal to 300.
Answer:
1) 91
Step-by-step explanation:
28 + 63 = 91
10 to the 2nd power only means 10x10=100
35.6/100=0.256
35.6/10x10=0.256