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2 years ago

Complete the table of pork sandwiches to chicken

Mathematics

1 answer:

denis-greek [22]2 years ago

4 0

Step-by-step explanation:

Pork sandwiches: 2 , 6 , 10 , 14

goes by 4

Chicken Sandwiches: 5 , 15 , 25 , 35

goes by 10

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What is the largest integer n such that (n^2-38) / (n +1) is an integer?

Phantasy [73]

Answer:

a. 36

Step-by-step explanation:

for (n^2-38)/(n+1) to be an integer, n+1 must completely divide, n^2-38.

we check with the options

option a n=36 sutisfies the above condition.

(36^2-38)/36+1 = 1258/37= 34 , which is an integer. Therefore, largest integer would be 36

6 0

2 years ago

Factor 30b2 + 48b - 24

iogann1982 [59]

IM going to assume that the "2" is to be squared. If so, then the answer is 2(15x^2+8)

6 0

2 years ago

from 1970 to 1980 the consumer price index increased from 38.8 to 82.4. If a container of onion dip cost $0.48 in 1970 and the p

Vikki [24]

We need to find the percent increase from 38.8 to 82.4, so

x * 38.8 = 82.4
x = 82.4/38.8
x = 2.1237

Multiply by 100 to convert to percentage (move decimal 2 places to the right)

2.1237 = 212.37%

Now we can apply this percentage increase to the onion dip...

0.48 x 212.37% =
0.48 x 2.1237 = 1.019

Round to the nearest cent $1.02 is the amount of increase. Now add it to the original price to get today's price...

$1.02 + .48 = $1.50

5 0

3 years ago

Read 2 more answers

8. Lilly paid $19.16 for a 1kg apple basket. This amount includes a tax of 3%. What was the cost of the apple before tax?

Maslowich

Answer:

19.75. The apples cost 19.75 before the tax.

Step-by-step explanation:

0.97(x)=19.16

19.75

7 0

2 years ago

Suppose that an airline overbooks seats on their flights. In particular, it sells 300 tickets for a flight when there are only 2

vladimir1956 [14]

Using the normal approximation to the binomial, it is found that there is a 0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

In this problem:

15% do not show up, so 100 - 15 = 85% show up, which means that $p = 0.85$ .
300 tickets are sold, hence $n = 300$ .

The mean and the standard deviation are given by:

$\mu = np = 300(0.85) = 255$

$\sigma = \sqrt{np(1-p)} = \sqrt{300(0.85)(0.15)} = 6.185$

The probability that we will have enough seats for everyone who shows up is the probability of at most 270 people showing up, which, using continuity correction, is $P(X \leq 270 + 0.5) = P(X \leq 270.5)$ , which is the p-value of Z when X = 270.5.

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{270.5 - 255}{6.185}$

$Z = 2.51$

$Z = 2.51$ has a p-value of 0.994.

0.994 = 99.4% probability that we will have enough seats for everyone who shows up.

A similar problem is given at brainly.com/question/24261244

8 0

2 years ago