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djverab [1.8K]
3 years ago
5

Find the surface area of the cylinder in terms of ​.

Mathematics
2 answers:
otez555 [7]3 years ago
3 0
Surface area = πr² + 2πrh

Surface area =  π(6)² + 2π(6)(12) = 180π cm²

Answer: 180π cm²
wlad13 [49]3 years ago
3 0
Surface area = πr² + 2πrh

Surface area =  π(6)² + 2π(6)(12) = 180π cm²

Answer: 214π cm²
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Expand and simpilify (x+2)(x+1)
Cerrena [4.2K]

Answer:

x^2+3x+2

Step-by-step explanation:

(X+2)(x+1)

Is x^2+x+2x+2

x^2+3x+2

4 0
3 years ago
Would someone just answer this now?
QveST [7]

Answer

20 degrees

Step-by-step explanation:

if m=20 on the otherside and point d marks the middle and a line is going through it it should be the same as the otherside

7 0
3 years ago
Sin5A/SinA-cos5A/cosA=4cos2A​
irina1246 [14]

Answer:

See Explanation

Step-by-step explanation:

\frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}  = 4\cos2A \\  \\ LHS = \frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}   \\  \\  =  \frac{ \sin5A \:\cos A -  \cos5A \:  \sin A}{\sin A \:\cos A }  \\  \\  =  \frac{ \sin(5A -A )}{\sin A \:\cos A}  \\  \\ =  \frac{ \sin 4A}{\sin A \:\cos A}  \\  \\ =  \frac{ 2\sin 2A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =  \frac{ 2 \times 2\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =  \frac{ 4\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A}  \\  \\ =4\cos 2A \\  \\  = RHS \\  \\ thus \\  \\  \frac{ \sin5A}{\sin A}  -  \frac{ \cos5A}{\cos A}  = 4\cos2A \\  \\ hence \: proved

5 0
3 years ago
1) m - 38 = -44 * m = --6 o m = 6 m = 82 O m = --82​
galina1969 [7]

m-38=-44

    +38     +38       add 38 on both sides, solve for -44 + 38 which is -6.

__________

m = -6, is your final answer.

hope this helps :)

8 0
3 years ago
Kenji packed an exercise ball into a cylindrical package . How much space does the package occupy in terms of pi . Enter your an
grandymaker [24]

Answer:

The space that the package would occupy is 45\pi cubic feet.

Step-by-step explanation:

The space that the package occupies is the volume of the cylinder. The volume of an object is the 3 dimensional capacity of the object.

Volume of a cylinder = \pir^{2}h

where: r is the radius and h is the height of the cylinder.

Given that; h = 5 feet and r = 3 feet.

The required volume = \pi × (3)^{2} × 5

                                   = \pi  × 9 × 5

                                  = 45\pi cubic feet

The space that the package would occupy is 45\pi cubic feet.

3 0
3 years ago
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