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Nady [450]
3 years ago
9

Ilang metro ang 1300 sentimetro?a. 1metrob. 13 metroc. 130 metro​

Mathematics
1 answer:
Pie3 years ago
4 0

Answer:

1300 cm = 13 m

Step-by-step explanation:

We need to find meters in 1300 cm.

We know that,

1 m = 100 cm

1 cm = (1/100) m

It means,

1300\ cm=\dfrac{1300}{100}\ m\\\\=13\ m

Hence, there are 13 m in 1300 cm.

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1. The sum of two consecutive integers is at least 23. What is the smallest value that will make the statement true?
Volgvan

Answer:

1- 11+ 12 = 23

2- -7 + -6 = -13

7 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST AND 100 POINTS
ICE Princess25 [194]

Answer:

a) The interval for those who want to go out earlier is between 43.008 and 46.592

b) The interval for those who want to go out later is between 47.9232 and 51.9168

Step-by-step explanation:

Given that:

Sample size (n) =128,

Margin of error (e) = ±4% =

a) The probability of those who wanted to get out earlier (p) = 35% = 0.35

The mean of the distribution (μ) = np = 128 * 0.35 = 44.8

The margin of error = ± 4% of 448 = 0.04 × 44.8 =  ± 1.792

The interval = μ ± e = 44.8 ± 1.792 = (43.008, 46.592)

b) The probability of those who wanted to start school get out later (p) = 39% = 0.39

The mean of the distribution (μ) = np = 128 * 0.39 = 49.92

The margin of error = ± 4% of 448 = 0.04 × 49.92 =  ± 1.9968

The interval = μ ± e = 44.8 ± 1.792 = (47.9232, 51.9168)

The way for those who want to go out earlier to win if the vote is counted is if those who do not have any opinion vote that they want to go earlier

4 0
3 years ago
Find upper and lower limit of a weight of a cotton reel which is 1.56g nearst to mg
Papessa [141]

Answer: the lower limit is 1.555g and the upper limit is 1.564g

Step-by-step explanation:

a mg is:

1mg = 0.001g

Then we need to look at the third digit after the decimal point.

Then the weight 1.56g is rounded around this.

Remember that if the third digit after the decimal point is 5 or bigger, then we round up.

if the third digit is smaller than 5, then we round down.

Now, the maximum possible value of this weight is when the third digit is equal to 4 (4 mg) where because it is smaller than 5, we round it down to 1.56g

Then the maximum is 1.564g

And the minimum value is when we have:

w = 1.555g

Because the third digit is a 5, we round it up to 1.56g.

So the lower limit is 1.555g and the upper limit is 1.564g

4 0
3 years ago
Solve Sec(2x)-4=0 for the first two positive solutions. thanks!
SSSSS [86.1K]

Answer:

2e-78

Step-by-step explanation:

a lot of factorials bruuru

6 0
3 years ago
Plz give answer fast.
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Answer:

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