F(n) = 1st term - common difference (n - 1)
The operation is subtraction because the sequence is decreasing.
n = number of the term you are looking for
1st term = 1st number in the sequence, in this case, 16
common difference = difference between one number to the next
f(n) = 16 - 1(n-1)
Assuming we are looking for the 5th term.
f(5) = 16 - 1(5-1)
= 16 - 1(4)
= 16 - 4
= 12 * as you can see, 12 is the 5th term of the sequence.
If you are looking for the equivalent of the nth term, simply substitute n by the number you are looking for and solve the equation.
It's 7
Hope I helped! ( Smiles )
Answer:
\frac{x^4+5}{x^3(x^2+6)} =\frac{A}{x}+\frac{B}{x^2}+\frac{D}{x^3} +\frac{Ex+F}{x^2+6}
Step-by-step explanation:
Answer: the first one -2+5i
Step-by-step explanation: because if we just take out the parenthesis the we can do it like a regular equation so 6-8 is -2 and 2i - -3i the 2 negatives gives us a positive so we get 2i+3i and get 5i so the equation would be -2+5i
