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g100num [7]
3 years ago
11

What is the slope of the line that passes through the points (-9, -8)((−15,−16)? Write your answer in simplest form.

Mathematics
1 answer:
alexandr402 [8]3 years ago
4 0

Answer:

Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is

Slope=\dfrac{4}{3}

Step-by-step explanation:

Given:

Let,

point A( x₁ , y₁) ≡ ( -9 ,-8)

point B( x₂ , y₂ )≡ (-15 ,-16)

To Find:  

Slope = ?

Solution:

Slope of Line Segment AB is given as

Slope(AB)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }

Substituting the values we get

Slope(AB)=\dfrac{-16-(-8)}{-15-(-9)}\\\\Slope(AB)=\dfrac{-16+8}{-15+9}\\\\Slope(AB)=\dfrac{-8}{-6}=\dfrac{4}{3}

Therefore the slope of the line that passes through the points (-9, -8),(−15,−16) is

Slope(AB)=\dfrac{4}{3}

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En un triángulo rectángulo A es un ángulo agudo y Sen A = 4/5 ¿Cuál será el valor de Tan A?
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Answer:

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Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

sen^2A+cos^2A=1

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

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Sustituyendo:

\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2

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Tomando raíz cuadrada:

\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}

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Substituyendo:

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