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MrRa [10]
3 years ago
12

(Best Buy Part A) At a Best Buy store, the forecast for the annual demand of a Motorola cell phone is 15600. Demand forecasts ar

e updated weekly and the unit time is one week. Motorola takes 2 weeks to supply an order and the setup cost is $400 per order. The holding cost rate is 10% and one cell phone costs $50. (Best Buy Part A) (a) What is the total setup cost? [Answer format: two decimal places] (b) What is the total holding cost? [Answer format: integer] (c) What is the total cost? [Answer format: two decimal places] (Note: To avoid rounding errors, use exactly the same order quantity in a previous question.) Write your answer(s) as 1234.56, 7891, 2345.67
Computers and Technology
1 answer:
Nataly_w [17]3 years ago
8 0

Explanation:

a. The computation of the economic order quantity is shown below:

= \sqrt{\frac{2\times \text{Annual demand}\times \text{Ordering cost}}{\text{Carrying cost}}}

= \sqrt{\frac{2\times \text{\15,600}\times \text{\$400}}{\text{\$5}}}

= 1,580 units

The carrying cost is

= $50 × 10%

= $5

b. The number of orders would be equal to

= Annual demand ÷ economic order quantity

= 15,600 ÷ 1,580

= 9.87 orders

Ordering cost = Number of orders × setup cost per order

= 9.87 orders × $400

= $3,949.37

c. The average inventory would equal to

= Economic order quantity ÷ 2

= 1,580 units ÷ 2

= 790 units

Carrying cost = average inventory × carrying cost per unit

= 790 units × $5

= $3,950

c. Now the total cost

= Setup cost + carrying cost

= $3,949.37 + $3,950

= $7,899.37

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Answer:

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7 0
3 years ago
Write a program that will ask for the user to input a filename of a text file that contains an unknown number of integers. And a
Ratling [72]

Answer: Provided in the explanation section

Explanation:

Code provided below in a well arranged format

inputNos.txt

70

95

62

88

90

85

75

79

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82

88

81

93

75

78

62

55

89

94

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___________________

StandardDev.java

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

public class StandardDev {

public static void main(String[] args) {

//Declaring variables

String filename;

int count = 0, i = 0;

Scanner sc1 = null;

int min, max;

double mean, stdDev;

int nos[] = null;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

//Getting the input entered by the user

System.out.print("Enter the name of the filename :");

filename = sc.next();

try {

//Opening the file

sc1 = new Scanner(new File(filename));

//counting no of numbers in the file

while (sc1.hasNext()) {

sc1.nextInt();

count++;

}

sc1.close();

sc1 = new Scanner(new File(filename));

//Creating an Integer based on the Count

nos = new int[count];

//Populating the values into an array

while (sc1.hasNext()) {

nos[i] = sc1.nextInt();

i++;

}

sc1.close();

//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

mean = calMean(nos);

stdDev = calStandardDev(nos, mean);

//Displaying the output

System.out.println("Read from file :" + count + " values");

System.out.println("The Minimum Number is :" + min);

System.out.println("The Maximum Number is :" + max);

System.out.printf("The Mean is :%.2f\n", mean);

System.out.printf("The Standard Deviation is :%.2f\n", stdDev);

} catch (FileNotFoundException e) {

e.printStackTrace();

}

}

//This method will calculate the standard deviation

private static double calStandardDev(int[] nos, double mean) {

//Declaring local variables

double standard_deviation = 0.0, variance = 0.0, sum_of_squares = 0.0;

/* This loop Calculating the sum of

* square of eeach element in the array

*/

for (int i = 0; i < nos.length; i++) {

/* Calculating the sum of square of

* each element in the array    

*/

sum_of_squares += Math.pow((nos[i] - mean), 2);

}

//calculating the variance of an array

variance = ((double) sum_of_squares / (nos.length - 1));

//calculating the standard deviation of an array

standard_deviation = Math.sqrt(variance);

return standard_deviation;

}

//This method will calculate the mean

private static double calMean(int[] nos) {

double mean = 0.0, tot = 0.0;

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Calculating the sum of all the elements in the array

tot += nos[i];

}

mean = tot / nos.length;

return mean;

}

//This method will find the Minimum element in the array

private static int findMinimum(int[] nos) {

int min = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] < min)

min = nos[i];

}

return min;

}

//This method will find the Maximum element in the array

private static int findMaximum(int[] nos) {

int max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

}

return max;

}

}

_____________________

Output:

Enter the name of the filename :inputNos.txt

Read from file :22 values

The Minimum Number is :50

The Maximum Number is :95

The Mean is :78.45

The Standard Deviation is :12.45

cheers i hope this helped !!!

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