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Andreas93 [3]
3 years ago
14

An initially uncharged 3.53 × 10 − 6 F capacitor and a 7290 Ω resistor are connected in series to a 1.50 V battery that has negl

igible internal resistance. What is the initial current I 0 in the circuit?
Physics
1 answer:
GarryVolchara [31]3 years ago
3 0

Answer:

The initial current, Io = 2.06×10^-4A

Explanation:

The I itial current ,Io of a circuit is given by:

Io = Vo/R

Where Vo = initial votage

R = resistance in ohms

Given:

Vo = 1.50V

R = 7290ohms

Io = 1.50/ 7290

Io = 2.06 ×10^-4A

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Answer:

When broadcasting live on social, keep in mind that the best broadcasts are ones that feel like a conversation between brand and viewer. Unlike other forms of social video, you’ll get more views and engagement if your video

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3 years ago
Two children, Ferdinand and Isabella, are playing with a water hose on a sunny summer day. Isabella is holding the hose in her h
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Answer:

Isabella will not be able to spray Ferdinand.

Explanation:

We'll begin by calculating the time taken for the water to get to the ground from the hose held at 1 m above the ground. This can be obtained as follow:

Height (h) = 1 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =.?

h = ½gt²

1 = ½ × 9.8 × t²

1 = 4.9 × t²

Divide both side by 4.9

t² = 1/4.9

Take the square root of both side

t = √(1/4.9)

t = 0.45 s

Next, we shall determine the horizontal distance travelled by the water. This can be obtained as follow:

Horizontal velocity (u) = 3.5 m/s

Time (t) = 0.45 s

Horizontal distance (s) =?

s = ut

s = 3.5 × 0.45

s = 1.58 m

Finally, we shall compare the distance travelled by the water and the position to which Ferdinand is located to see if they are the same or not. This is illustrated below:

Ferdinand's position = 10 m

Distance travelled by the water = 1.58 m

From the above, we can see that the position of the water (i.e 1.58 m) and that of Ferdinand (i.e 10 m) are not the same. Thus, Isabella will not be able to spray Ferdinand.

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what will happen to the brightness of the other bulbs in a series circuit if any of the bulbs were to burn out?
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Answer:

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