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3 years ago

The image shows a portion of the periodic table. Which two elements have similar characteristics?

Physics

2 answers:

inn [45]3 years ago

6 0

Answer:

Chlorine and Fluorine

Explanation:

When you look at our descriptions of the elements fluorine and chlorine, you will see that they both have seven electrons in their outer shell. That seven-electron trait applies to all of the halogens. They are all just one electron shy of having full shells.

Inessa05 [86]3 years ago

5 0

Answer:

F And AR i think

Explanation:

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Please help I’m a senior trying to graduate <br><br> Work as area under curve

Stells [14]

I need a picture to help you

8 0

3 years ago

Using the diagram shown, what is the magnitude of the resultant of these three forces?

amid [387]

Explanation:

The x component of the resultant force is the sum of the x components of the individual forces.

Fₓ = 65.0 cos 30° − 20.0 sin 20° − 30.0

Fₓ = 19.5

The y component of the resultant force is the sum of the y components of the individual forces.

Fᵧ = 65.0 sin 30° − 20.0 cos 20°

Fᵧ = 13.7

The magnitude is found with Pythagorean theorem:

F² = Fₓ² + Fᵧ²

F² = (19.5)² + (13.7)²

F = 23.8

5 0

3 years ago

A. Draw the electric field lines around a negative charge.

Alborosie

<h2>a. Answer:</h2>

We use Electric field lines for visualizing electric fields, so this helps us to see the problem more real. So an electric field line is an imaginary line or curve drawn through a region of space such that the tangent at any point comes from the direction of the electric-field vector at that point. The electric field lines around a negative charge is shown in the First figure below.

<h2>b. Answer:</h2>

Electric forces can be found by using the Coulomb Law's that states <em>that The magnitude of the electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. </em>This can be expressed as follows:

$F=k\frac{\left | q_{1}q_{2} \right |}{r^2} \\ \\ Where: \\ \\ k=9\times 10^9Nm^2/c^2 \\ \\ q_{1}=0.00150 C \ and \ q_{2}=0.00240 C \\ \\ r=0.900 m$

Then:

$F=9\times 10^9\frac{\left | 0.00150 \times 0.00240 \right |}{(0.900)^2} \\ \\ \therefore \boxed{F=40000N}$

This force is repulsive because the two charges are positive and recall that two positive charges or two negative charges repel each other while a positive charge and a negative charge attract each other.

<h2>C. Answer:</h2>

From the statement, we have two charged objects. Let's say that this charges are:

$q_{1} \ and \ q_{2}$

If the amount of charge on one of the objects is tripled, let's say this is the charge $q_{2}$ , then the new charge is:

$q_{N}=3q_{2}$

In the formula of Coulomb:

$F=k\frac{\left | q_{1}q_{N} \right |}{r^2} \\ \\ \therefore F=k\frac{\left | q_{1}(3q_{2}) \right |}{r^2} \\ \\ \therefore \boxed{F=3k\frac{\left | q_{1}q_{2} \right |}{r^2}}$

<em>The conclusion is that if the amount of charge on one of the objects is tripled, the electric force between two charged objects is also tripled</em>

<h2>d. Answer:</h2>

Let's use the Coulomb's Law again to solve this problem. We want to know how the electric force between two charged objects changes if the charges are moved closer together:

$F=k\frac{\left | q_{1}q_{N} \right |}{r^2}$

<em>By saying that the charges are moved closer together, we want to express that r becomes smaller. Since r is in the denominator, this implies that the electric force between these two charged objects becomes greater.</em>

<h2>e. Answer:</h2>

From the figure, we can see a metal sphere on a stand. There we have both positive and negative charges. We can say that the positive charge of this sphere is +10q and the negative and the negative charge is -10q. Since the electric charge is conserved, then the algebraic sum of all the electric charges in any closed system is constant. In conclusion, <em>the sphere has no net charge.</em>

<h2>f. Answer:</h2>

Here we want to know how the negative charges in the same sphere are redistributed when a positively charged rod is brought near it. Therefore, positive charge on rod repels positive charges on the sphere, creating zones of negative and positive charge as indicated in the second Figure.

7 0

3 years ago

Read 2 more answers

a rod of zinc has a mass of 5kg. in water it weighs 25 N. what is the buoyant force on it when it is submerged in water?

Alexxandr [17]

Answer:

If it has a mass of 5 kg its weight is 5 kg * 9.8 m/s^2 = 49 N

Weight in air = 49 N

Weight in water = 25 N

Buoyant force provided by water = 49 - 25 = 24 N

7 0

3 years ago

An airplane is flying at 300 mi/h at 4000 m standard altitude. As is typical, the air velocity relative to the upper surface of

posledela

Answer:

57330.17766 Pa

Explanation:

$P_1$ = Pressure at 4000 m = 61660 Pa

$\rho$ = Density at 4000 m = 0.8194 kg/m³

(Values taken from table of properties of air)

$V_1$ = Velocity of jet = $300\times \frac{1609.34}{3600}=134.11\ m/s$

$V_2$ = Velocity at max thickness

$V_2=1.26V_1=1.26\times 134.11=168.9786\ m/s$

From Bernoulli's equation

$P_1+\frac{1}{2}\rho V_1^2=P_2+\frac{1}{2}\rho V_2^2\\\Rightarrow P_2=P_1+\frac{1}{2}\rho V_1^2-\frac{1}{2}\rho V_2^2\\\Rightarrow P_2=61660+\frac{1}{2}\times 0.8194\times 134.11^2-\frac{1}{2}\times 0.8194\times 168.9786^2\\\Rightarrow P_2=57330.17766\ Pa$

The absolute pressure at this point on the wing is 57330.17766 Pa

3 0

4 years ago