The angle theta of the spring is 31 degrees. To solve for this, show the equation which is equal to the 10lb ball. With this, the unknown will be the angle. Then transpose/transfer the terms in order to isolate the variable for the angle. First solve for s, then solve for angle theta. You will come up with s = .5849 ft and angle theta = 31.2629 or 31 degrees. Hope this helps.
Answer:
Explanation:
Given:
dI/dt = 6.21 A/s
n = N/l
= 100 turns/cm
= 100 turns/cm × 100 cm/1 m
Radius, r = 14.7 cm
= 0.147 m
Inductance, L = uo × n^2 × A × l
L/l = 4pi × 10^-7 × (100 × 100)^2 × pi × 0.147^2
= 8.53 H
Emf, E = L × dI/dt
E/l = L/l × dI/dt
= 8.53 × 6.21
= 52.98 V/m
=
Answer:
4.43 kW
Explanation:
Since Intensity I = P/A = E²/2cμ₀ where P = Power, A = Area = 4πr² where r = distance from source = 61 m and E = electric field amplitude = 8.45 V/m.
P = E²A/2cμ₀ = E²4πr²/2cμ₀ = 2πE²r²/cμ₀
= 2π(8.45 V/m)²(61 m)²/3 × 10⁸ m/s × 4π × 10⁻⁷ Tm/A
= 4428.1 W
= 4.4281 kW ≅ 4.43 kW
Answer:
122.5 ohm
Explanation:
Given :
P=40 w
V= 70 V
R=?
Resistance can be calculated as :
Therefore, resistance of the bulb will be 122.5 ohm
