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3 years ago

What is the center of the circle shown below

Mathematics

2 answers:

scoray [572]3 years ago

5 0

Answer:

Theres no circle here.

Step-by-step explanation:

U forgot to insert it

Bogdan [553]3 years ago

3 0

Answer:

yeah theres no circle bud

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

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Ram wants to work to preserve marine habitats. Which field of study would be most useful to him

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Oceanography the others are other studies

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If y = 12 x – 12, determine the value of y when x = –16.

GrogVix [38]

Answer:

Step-by-step explanation: y=180

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3 years ago

Martin deposits $200 in a savings account that earns 5% annual interest. four years later, cary deposits $200 in an account earn

Scrat [10]

Martin deposits $200 in a savings account that earns 5% annual interest.

year interest balance

1 200 * 5% 200(1.05)

2 200(1.05) * 5% 200(1.05)^2

3 200(1.05)^2*5% 200(1.05)^3

y 200(1.05)^y

=> m = 200 (1.05)^y

four years later, cary deposits $200 in an account earning the same interest.


year interest balance

5 200 * 5% 200(1.05)

6 200(1.05) * 5% 200(1.05)^2

7 200(1.05)^2*5% 200(1.05)^3

y 200(1.05)^(y-4)

=> c = 200(1.05)^ (y-4)

Answer:
Martin: 200(1.05)^y
Cary: 200(1.05)^(y–4)

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3 years ago

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A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

What is the center of the circle shown below​

What is the center of the circle shown below