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nika2105 [10]
3 years ago
8

Yuma is solving the inequality 3x−23≥−5.

Mathematics
2 answers:
Mademuasel [1]3 years ago
6 0

3x \geqslant 23 - 5 \\ 3x \geqslant 18 \\ x \geqslant 6 \\

ololo11 [35]3 years ago
5 0

Answer:      x≥ 6

Step-by-step explanation:

To solve this inequality

3x - 23 ≥ -5

First, what you need to do is to add 23 to both-side of the inequality, Hence;

3x  -23  +  23  ≥ -5 + 23

(-23 + 23  = 0,   also  -5 +  23  = 18)

3x   ≥   18

To get the value of x, we need to divide both-side of the inequality by 3

3x /  3       ≥   18/3

(On the left hand side of the equation, the three at the numerator will cancel out that of the denominator, then on the right hand side of the equation, 3 will divide 18 which will give 6)

x ≥    6

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6 0
3 years ago
8x - 11 = -2x + 15 -5. What steps would you take to solve this?
MAVERICK [17]
Combine like terms. So that means combine the X's and combine the regular numbers.

- add 2x to 8x
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8 0
2 years ago
What so the tax cost $15 tax 5% what do I do
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7 0
2 years ago
Simplify 6 to the 5th power over 7 to the 3rd power times 2
Anon25 [30]
My answer -

<span>1. Use symbols (not words) to express quotient
 

2. Use exponent symbol (^) to denote exponents

3. Just write out question number, question, and choices. No need for extra information (such as points). Also, don't leave blank lines between choices. This extraneous that we don't need just makes your whole question very very long, and means a lot of scrolling on our part.
 

4. You should only post 2 or 3 questions at a time.


1) (6x^3 − 18x^2 − 12x) / (−6x) = −x^2 + 3x + 2 ----> so much simpler to read !

2) (d^7 g^13) / (d^2 g^7) = d^(7−2) g^(13−7) = d^5 g^6 ----> much easier to read !

3) (4x − 6)^2 = 16x^2 − 24x − 24x + 36 = 16x^2 − 48x + 36

4) (x^2 / y^5)^4 = (x^2)^4 / (y^5)^4 = x^8 / y^20

5) (3x + 5y)(4x − 3y) = 12x^2 − 9xy + 20xy − 15y^2 = 12x^2 + 11xy − 15y^2

6) (3x^3y^4z^4)(2x^3y^4z^2) = (3*2) x^(3+3) y^(4+4) z^(4+2) = 6 x^6 y^8 z^6

7) 5x + 3x^4 − 7x^3 ----> Fourth degree trinomial

8) (5x^3 − 5x − 8) + (2x^3 + 4x + 2) = 7x^3 − x − 6

9) (x − 1) + (2x + 5) − (x + 3) = x + 1

10) (−4g^8h^5k^2)0(hk^2)^2 = 0 (anything multiplied by 0 = 0)
or.. (−4g^8h^5k^2)^0(hk^2)^2 = 1 (h^2 (k^2)^2) = h^2 k^4

Last question shows why it is so important to use proper symbols (such as ^ to indicate exponents). Without such symbols, I could not tell if the 0 was an actual number and part of multiplication, of if 0 was an exponent of the expression preceding it.


P.S

Glad to help you have an AWESOME!!! day :)
</span>
6 0
3 years ago
Please help me :)), do not 'troll' with answers, it's graded...
wolverine [178]

The first one, decreasing then increasing

4 0
3 years ago
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