Answer:
9,32 . 7,16 . 3,8 . 5,8 . 3,4 . 1,2
in that order buddy make it exactly like this :)
I think you're asking if it's possible to have a cube root, fifth root, 7th root, etc of a number as a solution to f(x). The answer is yes it's possible.
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Example:
f(x) = x^3 - 29
This function has one real-number root of
(cube root of 29) and the other two roots are complex or imaginary roots.
Answer:
0.333333
Step-by-step explanation:
Hope this helps and have a great day!