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Monica [59]
2 years ago
7

The table shows the rate of melanoma by gender. mc026-1.jpg Consider the number of males who were diagnosed with melanoma in 200

5. What quantity does this number represent?
Biology
2 answers:
Novay_Z [31]2 years ago
8 0

The right answer is In 2005, 27.99 males out of every 100,000 were diagnosed with melanoma.

This number represents the incidence of melanoma (Skin cancer).

In epidemiology, incidence refers to the number of new cases of illness that have occurred during a given period of time. An increase in the incidence makes it possible for example to note an epidemic, even a pandemic. This data should not be confused with the prevalence, which refers to the number of people sick at a given time, or the incidence rate, which allows a better comparison of populations, by dividing the incidence by a representative sample of population (for example the number of cases per 100,000 people). The unit used to express the incidence is the number of new cases per person-time (example: 75 person-years).

Svetach [21]2 years ago
7 0
<span>In 2005, 27.99 males out of every 100,000 were diagnosed with melanoma.</span>
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Cystic fibrosis is most common in individuals of Northern European descent, affecting 1 in 3200 newborns. Assuming that these al
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0.0177

Explanation:

Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:

1/3200 = q² (have two CFTR mutant alleles) >>  

q = √ (1/3200) = 1/56.57 >>

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