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inn [45]
3 years ago
11

Please help me ! I will mark brainlist

Mathematics
2 answers:
RUDIKE [14]3 years ago
7 0

Answer:

900

Step-by-step explanation:

I used the box method

Mariana [72]3 years ago
3 0

Answer:

ha

Step-by-step explanation:

You might be interested in
A political polling agency predicts candidate A will win an election with 63% of the votes. Their poll has a margin of error of
scoray [572]

Answer:

56% ≤ p ≤ 70%

Step-by-step explanation:

Given the following :

Predicted % of votes to win for candidate A= 63%

Margin of Error in prediction = ±7%

Which inequality represents the predicted possible percent of votes, x, for candidate A?

Let the interval = p

Hence,

|p - prediction| = margin of error

|p - 63%| = ±7%

Hence,

Upper boundary : p = +7% + 63% = 70%

Lower boundary : p = - 7% + 63% = 56%

Hence,

Lower boundary ≤ p ≤ upper boundary

56% ≤ p ≤ 70%

5 0
3 years ago
Use the Factor Theorem to determine whether x + 1 is a factor of P(x) = 2x³+4x²–2x−8.
Harman [31]

Answer: 2x^2+2x-4-\frac{4}{x+1}

Not a factor because there is a remainder.

Step-by-step explanation:

Let's use synthetic division to solve this..

-1  ║ 2 | 4 | -2 | -8

   ║    | -2| -2 |  4

   ║ 2 | 2|  -4 |  -4

2x^2+2x-4-\frac{4}{x+1}

PS: if anyone knows a better way to do a synthetic division chart please let me know.

5 0
2 years ago
A sports teacher had 1025 sweets. After distributing these equally amongst all the participants in a sports meet, he had just 1
Cerrena [4.2K]

Step-by-step explanation:

Since it remains only 1 sweet, we can subtract it from the total and get the amount of sweets distributed (=1024).

As all the sweets are distributed equally, we must divide the number of distributed sweets by all its dividers (excluding 1024 and 1, we'll see later why):

1) 512 => 2 partecipants

2) 256 => 4 partecipants

3) 128 => 8 partecipants

4) 64 => 16 partecipants

5) 32 => 32 partecipants

6) 16 => 64 partecipants

7) 8 => 128 partecipants

9) 4 => 256 partecipants

10) 2 => 512 partecipants

The number on the left represents the number of sweets given to the partecipants, and on the right we have the number of the partecipants. Note that all the numbers on the left are dividers of 1024.

Why excluding 1 and 1024? Because the problem tells us that there remains 1 sweet. If there was 1 sweet for every partecipant, the number of partecipants would be 1025, but that's not possible as there remains 1 sweet. If it was 1024, it wouldn't work as well because the sweets are 1025 and if 1 is not distributed it goes again against the problem that says all sweets are equally distributed.

5 0
3 years ago
Use the diagram to answer the questions
IRISSAK [1]

Answer:

1.  B. BD

2. C. 15

3. A. 2

Step-by-step explanation:

1.  From the figure,

∠DAB = ∠DAC

Therefore, BD is the bisector of ∠ABC.


2.  From the figure, IG = GH

3x = 5x - 10

10 = 5x - 3x

2x = 10

x = 5

So, GH = 5x - 10

= 5(5) - 10

= 25 - 10

= 15

Therefore, GH = 15.


3.  From the figure,

∠DAB = ∠DAC

10y = 8y + 4

10y - 8y = 4

2y = 4

y = 2

8 0
3 years ago
PLEASE HELP ME
Vesnalui [34]

Step-by-step explanation:

-(3x+y=32)

3x-2y=17

-3x-y=-32

3x-2y=17

-3y=-15

y=5

3x+(5)=32

-5. -5

3x=27

x=9

Answer:

x=9

y=5

6 0
3 years ago
Read 2 more answers
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