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Triss [41]
3 years ago
7

This is easy but i’m having a bad day and this is almost due please help i will give brainliest

Mathematics
1 answer:
Serjik [45]3 years ago
7 0

Answer:

Step-by-step explanation:

okay so if we lay it out...,

f(x)              6-5x                x-9           x³           2x-5            12x+3

f(-3)              21                   12            -27           -11               -33

f(-2)              16                   -11           -8              -9                -21

f(0)                6                   -9             1                -5                 3

f(1)                 1                    -8             1                -3                 15

f(2)               -4                    -7            8               -1                   27

okay so the left side is all the f(x) values. So the numbers in the "()" represents "x". Now you just substitute the numbers in the"()" for the "x"'s on the top margins. so...,

f(-3)= 6-5x            f(-2)= 6-5x                 f(0)=6-5x               f(1)=6-5x        f(2)=6-5x

f(-3)= 6-5(-3)         f(-2)= 6-5(-2)             f(0)=6-5(0)            f(1)=6-5(1)       f(2)=6-5(2)

f(-3)= 6+15            f(-2)= 6+10                 f(0)=6-0                f(1)=6-5          f(2)=6-10

f(-3)= 21                f(-2)= 16                      f(0)=6                   f(1)= 1              f(2)= -4

f(-3)=x-9               f(-2)=x-9                      f(0)=x-9               f(1)=x-9            f(2)=x-9

f(-3)=(-3)-9            f(-2)=(-2)-9                  f(0)=0-9              f(1)=1-9             f(2)=2-9

f(-3)=-12                f(-2)=-11                       f(0)= -9                f(1)= -8            f(2)= -7

f(-3)=x³                 f(-2)=x³                        f(0)=x³                f(1)= x³              f(2)=x³

f(-3)=(-3)³             f(-2)= (-2)³                    f(0)=0³               f(1)=1³                f(2)=2³

f(-3)= -27             f(-2)= -8                        f(0)= 1                f(1)= 1                 f(2)=8

f(-3)= 2x-5           f(-2)= 2x-5                 f(0)= 2x-5            f(1)= 2x-5      f(2)=2x-5

f(-3)=2(-3)-5         f(-2)=2(-2)-5              f(0)= 2(0)-5          f(1)= 2(1)-5     f(2)=2(2)-5

f(-3)= -6-5            f(-2)= -4-5                  f(0)=0-5               f(1)=2-5         f(2)=4-5

f(-3)= -11               f(-2)= -9                      f(0)= -5                f(1)= -3          f(2)= -1

f(-3)=12x+3            f(-2)=12x+3              f(0)=12x+3          f(1)=12x+3     f(2)=12x+3

f(-3)= 12(-3)+3        f(-2)=12(-2)+3          f(0)=12(0)+3        f(1)=12(1)+3    f(2)=12(2)+3

f(-3)= -36+3          f(-2)= -24+3              f(0)= 0+3             f(1)=12+3       f(2)=24+3

f(-3)= -33                f(-2)= -21                  f(0)=3                 f(1)=15           f(2)= 27

Don't know if you wanted all the work. But I just did it for you so you can see.

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3 0
3 years ago
What are the solutions to x2 + 8x + 7 = 0?
Ymorist [56]
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6 0
3 years ago
Micheal solved this inequality as shown: step 1: -6(x + 3) + 10 < -2 step 2: -6x - 18 + 10 < -2 step 3: -6x - 8 < -2 st
Anastaziya [24]
<h3>Answer:   addition property of inequality</h3>

================================================

Explanation:

These are the steps to focus on

step 3: -6x - 8 < -2

step 4: -6x < 6

The move from the third step to the fourth step has us adding 8 to both sides. Therefore, we use the addition property of inequality.

That property has four forms

  1. If a > b then a + c > b+c
  2. If a < b then a+c < b+c
  3. If a \ge b then a + c \ge b+c
  4. If a \le b then a+c \le b+c

It's similar to the idea of starting with a = b, then adding c to both sides to get a+c = b+c

We add the same thing to both sides to keep things balanced.

8 0
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The plate is rotated 90° about the origin in the counterclockwise direction. In the image trapezoid, what are the coordinates of
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Answer:

The coordinates of the endpoints of the side congruent to side EF is:

E'(-8,-4) and F'(-5,-7).

Step-by-step explanation:

<em>" when point M (h, k) is rotated about the origin O through 90° in anticlockwise direction or we can say counter clockwise. The new position of point </em><em>M (h, k) will become M' (-k, h) "</em>

We are given a trapezoid such that the vertices of trapezoid are:

E(-4,8) , F(-7,5) , G(-4,3) , H(-2,5)

Then the new coordinates after the given transformation is:

E(-4,8) → E'(-8,-4)

F(-7,5) → F'(-5,-7)

G(-4,3) → G'(-3,-4)

H(-2,5) → H'(-5,-2)

Hence the coordinates of the endpoints of the side congruent to side EF is:

E'(-8,-4) and F'(-5,-7).


4 0
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