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2 years ago

Probability of a standard six side dice landing on a four in the first three rolls?

Mathematics

1 answer:

Illusion [34]2 years ago

6 0

Answer:

91/216

Step-by-step explanation:

The probability of getting a 4 in the first three rolls is 1 minus the probability of not getting a 4 on any of the rolls.

P(at least one 4) = 1 − P(no 4s)

P(at least one 4) = 1 − (5/6)³

P(at least one 4) = 91/216

Alternatively, you can calculate it this way.

The probability of getting a 4 on the first roll is 1/6.

The probability of getting a 4 on the second roll is (5/6) (1/6) = 5/36.

The probability of getting a 4 on the third roll is (5/6) (5/6) (1/6) = 25/216.

The probability of any of the three events is 1/6 + 5/36 + 25/216 = 91/216.

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The expression below is a sum of cubes. True or false<br> 64x^3+ 125<br> A. True<br> B. False

olchik [2.2K]

Answer:

True

Step-by-step explanation:

64x³ + 125

64x³ = (4x)³ ← a perfect cube

125 = 5³ ← a perfect cube

Thus 64x³ + 125 ← is a sum of cubes

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3 years ago

From 5 employees at a company, a group of 3 employees will be chosen to work on a project. How many different groups of 3 employ

Andrei [34K]

Hello,

aPb=b*(b-1)*(b-2)*....*(b-a+1) / a!

3P5=5*4*3/(3*2*1)=10

If we name the number of the employers 1,2,3,4,5

Here are the choices:

123,124,125,134,135,145,234,235,245,345 (total 10 choices)

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3 years ago

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Evaluate the expression. (38 + 10) ÷ 12 + 52

Mice21 [21]

48/12=4
4+52=56
Answer 56

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3 years ago

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Find the volume of a pyramid with a square base, where the side length of the base is

MatroZZZ [7]

Answer:

1529.4 m^3

Step-by-step explanation:

We will use the formula V = 1/3*h*B for the volume of the pyramid, where V is volume, h is height, and B is are of the base.

First, since we know h and are looking for V, we need B. To find this, since it has a square base, we multiply b, the base length, by itself. 15.3m * 15.3m = 234.09m^2.

Next, we plug into the formula.

V = 1/3*19.6m*234.09m^2

And simplify:

V= 1/3 * 4,588.164m^3

V= 15.29.3879....

Last, round to the tenth

1529.4 m^3

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3 years ago

The URS construction company has submitted two bids, one to build a large hotel in London and the other to build a commercial o

topjm [15]

Answer: Our required probability is 0.55.

Step-by-step explanation:

Since we have given that

Probability that chance of winning the hotel bid = 40%

Probability that no chance of winning the hotel bid = 100-40=60%

Probability that chance of winning the office building bid = 25%

Probability that no chance of winning the office building bid = 100-25 = 75%

So, Probability that the company will win at least one contract is given by

$0.4\times 0.75+0.6\times 0.25+0.4\times 0.25\\\\=0.55$

Hence, our required probability is 0.55.

5 0

3 years ago