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4 years ago

What is 6 5/3 x 5 7/8 < 42

Mathematics

1 answer:

Eddi Din [679]4 years ago

3 0

Answer:

The left side 45.041¯645.0416‾ is not less than the right side 42 which means that the given statement is false.

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Pirate Jack has an equal number of gold and silver coins. If Pirate Jack splits all of his coins into 7 equal piles for his parr

Tcecarenko [31]

Answer:

The least possible number of coins the Pirate has = 81

Step-by-step explanation:

Given:

Pirate Jack has equal number of gold and silver coins.

When the pirate splits the coins into 7 equal piles he has 4 coins left.

When the pirate splits the coins into 11 equal piles he has 4 coins left.

Every pile has at least 1 coin.

To find the least possible number of coins Pirate Jack has.

Solution:

In order to find the least possible number of coins pirate Jack has, we must find the least common multiple of the number of piles the coins are split into.

So, the least common multiple of 7 and 11 can be found by listing the multiples.

$7= 7,14,21,28...............,77$

$11=11,22,33,44,55,66,77$

So, we find the least common multiple of 7 and 11 is 77.

Number of coins left = 4

Total number of coins the pirate must have = $77+4 =81$

We can check the answer by dividing 81 by 7 and 11. I both cases we get remainder = 4.

So, the least possible number of coins the pirate has = 81

6 0

4 years ago

Is figure A’B’C’D’ a translation of figure ABCD? Explain.

natka813 [3]

D. I’m not for sure.

3 0

3 years ago

Read 2 more answers

Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati

Margaret [11]

Answer:

1. The minimum head breadth that will fit the clientele is of 4.41-in.

2. The maximum head breadth that will fit the clientele is of 7.19-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 5.8-in and a standard deviation of 0.8-in.

This means that $\mu = 5.8, \sigma = 0.8$