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2 years ago

A population was reduced from 3000 to 2500 in the ratio 5:y what is y

Mathematics

1 answer:

natka813 [3]2 years ago

4 0

Answer:

solution,

The population is reduced from 3000 to 2509 in the ratio 5:y

 $\frac{2500}{3000} = \frac{5}{y} \\ or \: 2500y = 15000 \\ or \: y = \frac{15000}{2500} \\ y = 6$ 

Hence,the ratio is 5:6.

hope this helps ....

Good luck on your assignment..

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Forty percent of households say they would feel secure if they had $50,000 in savings. you randomly select 8 households and ask

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Let X be the event of feeling secure after saving $50,000,

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Since, the binomial distribution formula,

$P(x=r)=^nC_r p^r q^{n-r}$

Where, $^nC_r=\frac{n!}{r!(n-r)!}$

If 8 households choose randomly,

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$P(X=5)=^8C_5 (0.4)^5 (0.6)^{8-5}$

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(b) the probability of the number that say they would feel secure is more than five

$P(X>5) = P(X=6)+ P(X=7) + P(X=8)$

$=^8C_6 (0.4)^6 (0.6)^{8-6}+^8C_7 (0.4)^7 (0.6)^{8-7}+^8C_8 (0.4)^8 (0.6)^{8-8}$

$=28(0.4)^6 (0.6)^2 +8(0.4)^7(0.6)+(0.4)^8$

$=0.04980736$

(c) the probability of the number that say they would feel secure is at most five

$P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)$

$=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}$

$=0.6^8+8(0.4)(0.6)^7+28(0.4)^2(0.6)^6+56(0.4)^3(0.6)^5+70(0.4)^4(0.6)^4+56(0.4)^5(0.6)^3$

$=0.95019264$

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