Answer:

Step-by-step explanation:
In this problem, we can use two methods to solve for the values of x (roots) of the given equation. Those methods are: using the quadratic formula and factoring.
Standard Form of a Quadratic Equation: ax² + bx + c = 0, where a ≠ 0
<u>Given equation:</u> 2x² + 7x + 6 = 0
⇒ a = 2, b = 7, c = 6
Method 1: Using the Quadratic Formula
<u>Quadratic Formula:</u> 
<u>Step 1:</u> Substitute the values of <em>a</em>, <em>b</em>, and <em>c</em> into the quadratic formula.

<u>Step 2:</u> Simplify

<u>Step 3:</u> Separate into two possible cases and solve for the values of x.

Method 2: Solve by Factoring
In order to be able to solve this equation by factoring, let's rewrite the <em>middle term</em> by finding the factors that give a product of the first and last terms (a • c = 12) and give us the sum of the middle term (b = 7).
Factors that give a product of a • c: <em>4 • 3</em> = 12
Factors that give a sum of b: <em>4 + 3</em> = 7
<u>Step 1:</u> Rewrite the given equation with those factors.
2x² + 7x + 6 = 0
⇒ 2x² + 4x + 3x + 6 = 0
<u>Step 2:</u> Factor out 2x and 3.
(2x² + 4x) + (3x + 6) = 0
⇒ 2x(x + 2) + 3(x + 2) = 0 [ Factor out the the common factor. ]
⇒ (2x + 3)(x + 2) = 0
<u>Step 3:</u> Apply the <em>Zero-Product Property</em> (if m•n = 0, then m = 0 or n = 0).
a) 2x + 3 = 0 ⇒ 2x = -3 ⇒ x = -³⁄₂
b) x + 2 = 0 ⇒ x = -2
Therefore, the two roots of this equation are x = -³⁄₂ and x = -2.
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