Question

10 points!!! Please show work!!

Answer 1

Answer:

Smaller $x=-14$

Larger $x=0$

Step-by-step explanation:

$(x+7)^2-49=0$

$(x+7)^2=49$ (add 49 to both sides)

$\sqrt{(x+7)^2} =\sqrt{49}$

Knowing that $7*7=49$ and $-7*-7=49$

$x+7=7$ or $x+7=-7$

Solving for $x+7=7$ first...

$x=0$ (subtract 7 from both sides)

Solving for $x+7=-7$

$x=-14$ (subtract 7 from both sides)

Answer 2

Answer:

Smallest x  -14

Larger x   0

Step-by-step explanation:

(x+7)^2 -49=0

Add 49 to each side

(x+7)^2 -49+49=0+49

(x+7)^2 = 49

Take the square root of each side

sqrt((x+7)^2) = ±sqrt(49)

x+7 = ±7

Subtract 7 from each side

x+7-7 = -7±7

x = -7±7

x = -7 -7       x = -7+7

x = -14             x =0

Smallest x  -14

Larger x   0