Question is Incomplete, Complete question is given below.
Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.
Answer:
∆ABC is right angled triangle with right angle at B.
Step-by-step explanation:
Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.
We need to prove that triangle is the right angled triangle.
Let the triangle be denoted by Δ ABC with side as;
AB = (a - 1) cm
BC = (2√ a) cm
CA = (a + 1) cm
Hence,
Now We know that

So;


Now;

Also;

Now We know that




[By Pythagoras theorem]

Hence, 
Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.
This proves that ∆ABC is right angled triangle with right angle at B.
Answer:
this only goes to the thousanths.
Step-by-step explanation:
Answer:
There are infinitely many solutions
Step-by-step explanation:
Firstly, I need to change f to x as the system won’t accept the word f
Let’s take a look at the question;
3 is less than x
The domain of our answer lies in the the range of values where we have numbers that are greater than 3
This means we can rewrite our inequality as x is greater than 3
Now, simply because we have an infinite amount of numbers which are greater than 3 of which x can take any of the values, we can conclude that the number of values we have for x are infinite and does not end
This makes us have infinitely many solutions for the value of x
1)
m = 3√2√2
= 6
n = a
= 3√2
<u>Answer = </u><u> </u><u>D</u><u>)</u><u> </u><u>m</u><u> </u><u>=</u><u> </u><u>6</u><u> </u><u>,</u><u> </u><u>n</u><u> </u><u>=</u><u> </u><u>3</u><u>√</u><u>2</u>
2)
m = n = a
m = 3
n = 3
<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u> </u><u>=</u><u> </u><u>A</u>
Do you have a picture to show, so that I can help?