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Jobisdone [24]
3 years ago
10

Choose the congruence theorem that you would use to prove the triangles congruent.

Mathematics
2 answers:
butalik [34]3 years ago
8 0
Your answer is ASA BUDDY
tankabanditka [31]3 years ago
7 0
The graph shows a congruent angle, then a line, then another congruent angle, so it is ASA
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Prove that a triangle with the sides a - 1 cm to root under a ​
vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.  

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm  

Hence,

{AB}^2 = (a -1)^2 

Now We know that

(a- b)^2 = a^2+b^2 - 2ab

So;

{AB}^2= a^2 + 1^2 -2\times a \times1

{AB}^2 = a^2 + 1 -2a

Now;

{BC}^2 = (2\sqrt{a})^2= 4a

Also;

{CA}^2 = (a + 1)^2

Now We know that

(a+ b)^2 = a^2+b^2 + 2ab

{CA}^2= a^2 + 1^2 +2\times a \times1

{CA}^2 = a^2 + 1 +2a

{CA}^2 = AB^2 + BC^2

[By Pythagoras theorem]

a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a

Hence, {CA}^2 = AB^2 + BC^2

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

4 0
3 years ago
Rou<br>Round 66.681 to the nearest ten thousand.​
Pavel [41]

Answer:

this only goes to the thousanths.

Step-by-step explanation:

7 0
3 years ago
Carol is solving the inequality 3 have?<br> There are infinitely many solutions.<br> There are only two solutions.<br> There is
schepotkina [342]

Answer:

There are infinitely many solutions

Step-by-step explanation:

Firstly, I need to change f to x as the system won’t accept the word f

Let’s take a look at the question;

3 is less than x

The domain of our answer lies in the the range of values where we have numbers that are greater than 3

This means we can rewrite our inequality as x is greater than 3

Now, simply because we have an infinite amount of numbers which are greater than 3 of which x can take any of the values, we can conclude that the number of values we have for x are infinite and does not end

This makes us have infinitely many solutions for the value of x

6 0
3 years ago
Hey guys ! Can anyone help me with these problems please and thanks
AnnyKZ [126]

1)

m = 3√2√2

= 6

n = a

= 3√2

<u>Answer = </u><u> </u><u>D</u><u>)</u><u> </u><u>m</u><u> </u><u>=</u><u> </u><u>6</u><u> </u><u>,</u><u> </u><u>n</u><u> </u><u>=</u><u> </u><u>3</u><u>√</u><u>2</u>

2)

m = n = a

m = 3

n = 3

<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u> </u><u>=</u><u> </u><u>A</u>

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2 years ago
The mean electric bill for Family C is approximately
Nata [24]
Do you have a picture to show, so that I can help?
8 0
3 years ago
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