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3 years ago

Jana And Jordan had 23 oranges Jana had 7 fewer oranges than Jordan how many oranges did each girl have

Mathematics

1 answer:

Solnce55 [7]3 years ago

3 0

Answer:

Jana had 8 oranges, and Jordan had 15 oranges.

Step-by-step explanation:

First, identify what you know:

1) In total, Jana and Jordan had 23 oranges.

2) Jana had 7 less oranges than Jordan.

We can create a formula, where x equals the number of oranges Jana has.

23 = x + (x + 7)

16 = x + x (subtracted 7 from both sides)

x = 8 (divided both sides by 2)

So, now we know Jana had 8 oranges, which is 7 less than Jordan.

8 + 7 = ?

? = 15

Jana had 8 oranges, while Jordan had 15, for a total of 23 oranges.

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80 to 10

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At the grocery store, Luis brought 10 bananas and 4 apple. What are three different ways to write the 4 ratio of apples to banan

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3 years ago

Fatima is shaping this model to show 0.08 x 3. shade the correct amount of boxes that will show the product. fatima should shade

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Answer:

Fatima should shade 3 groups of 8 small squares or 24 small squares.

Step-by-step explanation:

Consider the provided information.

Fatima is shading this model to show 0.08 × 3. Shade the correct amount of boxes that will show the product.

Here 3 represents the number of groups and 8 represents the small square.

Multiplication is repeated addition.

We can rewrite the above multiplication as: 0.08 + 0.08 + 0.08

Therefore 0.08 × 3 = 0.24

Here 0.24 represents 24 small squares.

The required model is shown below:

Hence, Fatima should shade 3 groups of 8 small squares or 24 small squares.

8 0

3 years ago

A toy rocket is launched straight up from the top of a building. The function that models the height as a function of time is h(

kicyunya [14]

Answer: 50 ft

Step-by-step explanation:

The correct function is h(t)=-16t^2+200t+50.

Hi, to answer this question we simply have to replace t =0 in the function given:

h(t)=-16t^2+200t+50.

h (0) = -16t^2+200t+50.

h(0) = 50

When the time is 0, the rocket is at the top of the building.

The rocket was launched from a 50 ft height.

Feel free to ask for more if needed or if you did not understand something.

4 0

3 years ago

K is the midpoint of PQ, P has

Pachacha [2.7K]

Answer:

Coordinates of Q $(x_2,y_2) \:are\: \mathbf{(7,16)}$

Option D is correct option.

Step-by-step explanation:

We are given:

K is the midpoint of PQ

Coordinates of P = (-9,-4)

Coordinates of K = (-1,6)

We need to find coordinates of Q $(x_2,y_2)$

We will use the formula of midpoint: $Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

We are given midpoint K and $x_1,y_1$ the coordinates of P we need to find $x_2,y_2$ the coordinates of Q.

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\$

Now, we can write

$-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16$

So, we get coordinates of Q $(x_2,y_2) \:are\: \mathbf{(7,16)}$

Option D is correct option.

6 0

3 years ago