The answer is y = -1/3x + 2
Because the y intersect is located at (0,2) we know that the b value in the formula y=mx + b is 2 and using rise over run we determine the slope to be -1/3
Answer:
I guess that you want to model the elevation of Lake Sam Rayburn.
During the summer, it is 165 ft above the sea level (the sea level is our position 0ft).
If it does not rain, the elevation of the lake decreases by 0.5ft each week.
So if we assume that there is no rain, we can write the elevation fo the lake as a linear relationship with slope equal to -0.5ft and y-intercept equal to 165ft.
L(w) = 165ft - 0.5ft*w
Where w is the number of weeks without rain, if we have 0 weeks without rain, then the level of the lake remains constant at 165ft above sea level,
L(0) = 165ft - 0.
You will need to add 8 to the other side of the equation to get t = -3 + 8
Answer:
Y=-1/3x+2
Reason:
the line is negative so it Goes down one right 3 and the line is on the positive 2 on the y axis.
Answer:
The height of the tank in the picture is:
Step-by-step explanation:
First, to know the height of the tank, we're gonna change the unit of the volume given in liters to cm^3:
- <em>1 liter = 1000 cm^3</em>
So:
- <em>1.2 liters = 1200 cm^3</em>
Now, we must calculate the height of the tank that we don't know (the other part that isn't with water), to this, we can use the volume formula clearing the height:
- Volume of a cube = long * wide * height
Now, we must clear the height because we know the volume (1200 cm^3):
Height = volume of a cube / (long * wide)
And we replace:
- Height = 1200 cm^3 / (12 cm * 8 cm)
- Height = 1200 cm^3 / (96 cm^2)
- Height = 12.5 cm
Remember this is the height of the empty zone, by this reason, to obtain the height of the whole tank, we must add the height of the zone with water (7 cm) that the exercise give us:
- Heigth of the tank = Height empty zone + height zone with water
- Heigth of the tank = 12.5 cm + 7 cm
- <u>Heigth of the tank = 19.5 cm</u>
In this form, <u>we calculate the height of the tank in 19.5 cm</u>.
