The standard equation of a circle is expressed as
(x - h)^2 + (y - k)^2 = r^2
where
h is the x coordinate of the center of the circle
k is the y coordinate of the center of the circle
r is the radius of the circle(the distance from the center of the circle to the circumference
From the graph,
h = - 1
y = 4
r = 5
By substituting these values into the equation, we have
(x - - 1)^2 + (y - 4)^2 = 5^2
(x + 1)^2 + (y - 4)^2 = 25
Thus, the equation of the circle is
(x + 1)^2 + (y - 4)^2 = 25
Answer:
\begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}
\begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)=1\:\\ \:\mathrm{Interval\:Notation:}&\:f\left(x\right)=1\end{bmatrix}
Step-by-step explanation:
Answer:76%
Step-by-step explanation:38 out of 50 equals 76%
32.5 % of lab are wireless devices
<em><u>Solution:</u></em>
Given that there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices
Now we can first find out total number of computers and devices in lab
total number of computers and devices in lab = 30 computers - 3 + 13 wireless devices
total number of computers and devices in lab = 30 - 3 + 13 = 40
So there are 40 computers and wireless devices in lab
<em><u>To find: what percent of the lab are wireless devices</u></em>
So we have to find what percent of 40 is 13
Let "a" be the required percent
a % of 40 = 13

32.5 % of of lab are wireless devices