Assume N students
Student 1 can get (n-1) papers
Student 2 can get (n-1) papers
Student 3 can get (n-1) papers
etc
Student N can get (n-1) papers
So for N students you can have N(n-1)
Mathrie 134x3= 402 ship names are my specialty:)
Answer:
system of equations
Step-by-step explanation:
You can eliminate one of the variable terms in a <u>system of equations</u> by adding or subtracting another equation.
Now, the cosecant of θ is -6, or namely -6/1.
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

recall that

therefore, let's just plug that on the remaining ones,

now, let's rationalize the denominator on tangent and secant,
Answer:
One adult ticket is $4 and one child ticket is $7
Step-by-step explanation:
Make a system of equations
2x + 10y = 78
8x + 5y = 67
Solve by elimination, multiply the 2nd equation by -2
2x +10y = 78
-16x -10y = -134
Add the equations
-14x = -56
x = 4
The price of one adult ticket is $4
Plug 4 in as x to find y
2(4) + 10y = 78
8 + 10y = 78
10y = 70
y = 7
The price of one child ticket is $7