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2 years ago

Which relation is a function?

Mathematics

2 answers:

brilliants [131]2 years ago

7 0

Answer:

The last one at the right

Step-by-step explanation:

It is a function because not of the x axis numbers are repeated.

Bumek [7]2 years ago

3 0

Answer:

The bottom right

Step-by-step explanation:

No two different coordinates in one value should have a repeating number in another

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Help asap please!!..

Semenov [28]

Answer:

9x² - 4/3x + ¼

Step-by-step explanation:

(3x - ½)²

(3x - ½)(3x -½)

9x² - ⅔x - ⅔x + ¼

9x² - 4/3x + ¼

5 0

2 years ago

What is the cotangent of angle G? A. 24/10 B. 13/12 C. 5/12 D. 12/10

sveta [45]

A.
Tangent is Opp/Adj
tan = 10/24

And cotan is tan flipped so
Adj/Opp

Cot= 24/10

A.

5 0

3 years ago

A triangle has the sides of 7 in, 14 in, and 25 in. Is it a right triangle?

MariettaO [177]

Answer:

No it does not equal a right triangle.

3 0

2 years ago

Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

3 years ago

(2,?) is on the line x + 3 = y. Find the other half of the coordinate.

Brut [27]

Sub in 2 for x and solve for y

x + 3 = y
2 + 3 = y
5 = y

so ur points are : (2,5)

4 0

3 years ago

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