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ValentinkaMS [17]
4 years ago
7

There are 5 red marbles, 8 blue marbles, and 12 green marbles in a bag.

Mathematics
2 answers:
dolphi86 [110]4 years ago
4 0
Total number of marbles: 
5+8+12 = 25

Probability of drawing red marble = red/total 
                                                         = 5/25 =1/5

Percentage of drawing red marble: 1/5 x 100 = 20%

Ans: 20%
cricket20 [7]4 years ago
3 0
  To find the percentage always multiply whatever decimal number you have by 100% <span>
1) 5 + 8 + 12 = 25 (total number in bag) 
5/25 x 100% (because you're trying to find probability of red) 
= 20% 

2) 5 + 8 = 13 (# of red AND blue) 
13/25 x 100% (divide out of the total) 
=52% 

3) 5/25 = 0.2 x 12/25 = 0.48 (find probability of drawing red and green) 
0.2 x 0.48 x 100% 
= 9.6% 

4) 10 + 12 + 28 = 50 (to find total number of trials) 
28/50 x 100% 
= 56% 

5) 5 x 7 (number of sections on first spinner multiply by # of sections on second spinner) 
= 35</span><span>Its B 20%


</span>
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The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




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