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Viefleur [7K]
3 years ago
7

How do I count by twelfths

Mathematics
1 answer:
Korvikt [17]3 years ago
8 0

12,  x 1 = 12

12 x 2 =24  

12 x 3 = 36

12 x 4 =48

12 x 5= 60  

12 x 6 =72  

 

12 x 7 = 84

 

12 x 8= 96

12 x 9= 108  

12 x 10 = 120  

 

12 x 11=132

12x 12= 144

hope this helps

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Solve the system of linear equations by substitution x=5y+2 and x-4y=5
never [62]

Answer:

(17,3)

Step-by-step explanation:

Equation 1.

x=5y+2

Equation 2.

x-4y=5

To solve with substitution, it looks like the x-variable in the first equation is already isolated. So, plug the first equation into the x-variable in the second equation.

x-4y=5

(5y+2)-4y=5

y+2=5

y=3

Now that we found y, plug y into one of the equations to solve for x.

x=5y+2

x=5(3)+2

x=15+2

x=17

(17,3)

6 0
3 years ago
What is the product of 5×10'5​
Oksanka [162]
(if the last five is an exponent, here is the answer)

5 • 10^5
first work on the exponent
5 • 100,000
multiply
500,000
6 0
4 years ago
PLEEEEEEASE HELP ME THIS IS VERY LATE WORK
kicyunya [14]
Part A: David wrote 0.003 + 0.0001 instead of <span>0.03 + 0.001 

Part B: T</span>he 1 should be in the thousandths place

Hope this helps, make sure to count each place from right after the decimal which is the tenths place, then hundredths, etc.
5 0
4 years ago
What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?
s344n2d4d5 [400]

Answer:

2 units

Step-by-step explanation:

The given equation of the circle is:

x^{2} + y^{2}+8x-6y+21=0

The general equation of the circle is:

x^{2} + y^{2}+2gx+2fy+c=0

Comparing the given equation with the general equation we can say:

g = 4

f = -3

c = 21

The formula for radius of the circle is:

radius=\sqrt{g^{2} +f^{2} -c }

Using these values of the given circle, we get:

radius=\sqrt{(4)^{2}+(-3)^{2}-21}\\\\radius=\sqrt{4}\\\\radius=2

Therefore, the length of radius of the given circle is 2.

3 0
3 years ago
Solve this equation. 5n+7=7(n+1)-2n
Trava [24]
5n + 7 = 7(n+1) - 2n

First distribute 7 to all terms inside the parenthesis

7(n) = 7n
7(1) = 7

5n + 7 = 7n - 2n + 7

Simplify. Combine like terms

5n + 7 = 5n + 7

True.

If you want to continue:

Isolate the n, move all variables to one side, and constants to the other

5n (-5n) + 7 (-7) = 5n (-5n) + 7 (-7)

0 = 0

True


hope this helps
6 0
3 years ago
Read 2 more answers
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