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3 years ago

Write an equation that shows the relationship between time and distance

Mathematics

1 answer:

gizmo_the_mogwai [7]3 years ago

8 0

Distance= Rate(speed) divided by Time(the amount of time it takes).

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How the heck do you do the onion skin math method?

topjm [15]

Answer:

The onion skin math method helps you understand

Step-by-step explanation:

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3 years ago

Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

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3 years ago

What is the ratio of hexagons to rectangles?

Butoxors [25]

Answer:

4:6

Step-by-step explanation:

um there is no picture to count from so i will created a random one which was 4:6

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3 years ago

It is estimated that there are approximately 1 × 1014 cells in the human body. Which of the following represents this amount in

serg [7]

1014 hope thts the awnser it seemed to obvious

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3 years ago

Jessica has $50 to spend on new clothes.

Zigmanuir [339]

Answer:

Answer: No

Step-by-step explanation:

You multiply 48 ×0.06 which is $2.88 in tax so it will bring the total to 51.08

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3 years ago