Answer:
The maximum height of the twig is 96.6 feet off the ground
Step-by-step explanation:
To determine the maximum height of the twig,
First, we will determine the height distance covered by the twig after Mary flicks the twig up.
From the question,
Mary flicks a twig up and off of the ledge with the initial vertical velocity of 10 feet per second, that is
the initial velocity of the twig is 10 feet/second
At maximum height, the final velocity is 0
From on the equations of motions for bodies moving upwards,
v² = u² - 2gh
Where v is the final velocity
u is the initial velocity
g is the acceleration due to gravity (Take g = 9.8m/s² = 32.17 ft/s²)
and h is the height
From the question
u = 10 feet/second
and v = 0 feet/second
Putting the values into the equation
v² = u² - 2gh
0² = 10² - 2(32.17)h
0 = 100 - 64.34h
64.34h = 100
h = 100/64.34
h = 1.6 feet
This is the height distance covered by the twig after Mary flicks it up.
Now, the maximum height of the twig will be the sum of the height of the rooftop from the ground and the height distance covered by the twig.
That is,
Maximum height = 95 feet + 1.6 feet
Maximum height = 96.6 feet
Hence, the maximum height of the twig is 96.6 feet off the ground.
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