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3 years ago

5

If someone could answer the second part that would be awesome thanks, no spam please

1 answer:

Zigmanuir [339]3 years ago

6 0

Answer:

c

Step-by-step explanation:

m<4 and m<3 is a straight angle. straight angles are equal to 180 degrees. the friend found m<3=40 and m<4 is equal to 140 degrees (im not good at explaining, sorry)

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A quarter is 1/4 dollar. Noah has 8 quarters. How much money does he have?

Dmitry_Shevchenko [17]

Answer:
noah has $2

step-by-step explanation:
1/4 * 8 = 8/4 = 2

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3 years ago

The surface area of a right cone is 400.2 m2. The radius of the cone is 6.0 m. Determine the height of the cone to the nearest m

svetoff [14.1K]

S = πr(r + √(h² + r²))
  400.2 = 3.14(6)(6 + √(h² + 6²))
  400.2 = 18.84(6 + √(h² + 36))
  18.84   18.84
  21¹⁰⁹/₄₇₁ = 6 + √(h² + 36))
  - 6 - 6
  15¹⁰⁹/₄₇₁ = √(h² + 36)
231²²¹⁰⁰⁵/₂₂₁₈₄₁ = h² + 36
- 36   - 36
195²²¹⁰⁰⁵/₂₂₁₈₄₁ = h²
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8 0

3 years ago

Solve −4(x + 10) − 6 = −3(x − 2).<br> a −40<br> b −46<br> c −52<br> d 52

12345 [234]

The answer is C. -52.

6 0

4 years ago

Read 2 more answers

Solving Rational Functions Hello I'm posting again because I really need help on this any help is appreciated!!

Greeley [361]

Answer:

x = √17 and x = -√17

Step-by-step explanation:

We have the equation:

$\frac{3}{x + 4} - \frac{1}{x + 3} = \frac{x + 9}{(x^2 + 7x + 12)}$

To solve this we need to remove the denominators.

Then we can first multiply both sides by (x + 4) to get:

$\frac{3*(x + 4)}{x + 4} - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

$3 - \frac{(x + 4)}{x + 3} = \frac{(x + 9)*(x + 4)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x + 3)

$3*(x + 3) - \frac{(x + 4)*(x+3)}{x + 3} = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$3*(x + 3) - (x + 4) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

$(2*x + 5) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}$

Now we can multiply both sides by (x^2 + 7*x + 12)

$(2*x + 5)*(x^2 + 7x + 12) = \frac{(x + 9)*(x + 4)*(x+3)}{(x^2 + 7x + 12)}*(x^2 + 7x + 12)$

$(2*x + 5)*(x^2 + 7x + 12) = (x + 9)*(x + 4)*(x+3)$

Now we need to solve this:

we will get

$2*x^3 + 19*x^2 + 59*x + 60 = (x^2 + 13*x + 3)*(x + 3)$

$2*x^3 + 19*x^2 + 59*x + 60 = x^3 + 16*x^2 + 42*x + 9$

Then we get:

$2*x^3 + 19*x^2 + 59*x + 60 - ( x^3 + 16*x^2 + 42*x + 9) = 0$

$x^3 + 3x^2 + 17*x + 51 = 0$

So now we only need to solve this.

We can see that the constant is 51.

Then one root will be a factor of 51.

The factors of -51 are:

-3 and -17

Let's try -3

p( -3) = (-3)^3 + 3*(-3)^2 + +17*(-3) + 51 = 0

Then x = -3 is one solution of the equation.

But if we look at the original equation, x = -3 will lead to a zero in one denominator, then this solution can be ignored.

This means that we can take a factor (x + 3) out, so we can rewrite our equation as:

$x^3 + 3x^2 + 17*x + 51 = (x + 3)*(x^2 + 17) = 0$

The other two solutions are when the other term is equal to zero.

Then the other two solutions are given by:

x = ±√17

And neither of these have problems in the denominators, so we can conclude that the solutions are:

x = √17 and x = -√17

6 0

3 years ago

A 1,600.00 principal earns 7% interest compounded semiannually twice per year' after 33 years what is the balance in the account

Dmitrij [34]

A=1600(1+0.07/2)^(2*33)=15,494.7

7 0

3 years ago