To find it, evaluate it at the endpoints and the vertex
in form
f(x)=ax²+bx+c
the x value of the vertex is -b/2a
given
c(t)=1t²-10t+76
x value of vertex is -(-10)/1=10
evaluate c(0) and c(13) and c(10)
c(0)=76
c(13)=115
c(10)=76
it reached minimum in 2000 and 2010
porbably teacher wants 2010
the min value is $76
Answer:
D. 20
Step-by-step explanation:
First, we need to plug in -2 to all the spots where x are. The new equation we have then is f(-2)= 2(-2)^2 - 3(-2) + 6. Then, we plug in the exponent to get 2(4) - 3(-2) + 6. We can then multiply to get 8 + 6 (since the three was negative as well) + 6, which equals 20.
Answer:
-x^2 - 11x -30
Step-by-step explanation:
Solve using foiling. Ignore the -1 to begin with and just look at the part in parenthesis. Do x from the first parenthesis times the stuff in the second parenthesis.
ie: x(x) and x(6)
ie: x^2 + 6x
Then do the 5 times the things in the second parenthesis.
ie: 5(x) and 5(6)
ie: 5x + 30
Then add what you got from multiplying the first value to what you got from multiplying the second.
ie: x^2 + 11x + 30
This is a trinomial because it has three different variables. Now change all the signs to negative because of the -1 out front.
ie: -x^2 - 11x -30
