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yKpoI14uk [10]
3 years ago
11

What is 61% percent written as a decimal? 100 points and Brainliest

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
5 0

Answer:

0.61

........

.......

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Juan lives 2.5 miles from the park. It took him 12 minutes to ride his bicycle to the park. What was Juan's average speed, in mi
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A certain paper suggested that a normal distribution with mean 3,500 grams and a standard deviation of 560 grams is a reasonable
Natalka [10]

Answer: the probability that a randomly selected Canadian baby is a large baby is 0.19

Step-by-step explanation:

Since the birth weights of babies born in Canada is assumed to be normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = birth weights of babies

µ = mean weight

σ = standard deviation

From the information given,

µ = 3500 grams

σ = 560 grams

We want to find the probability or that a randomly selected Canadian baby is a large baby(weighs more than 4000 grams). It is expressed as

P(x > 4000) = 1 - P(x ≤ 4000)

For x = 4000,

z = (4000 - 3500)/560 = 0.89

Looking at the normal distribution table, the probability corresponding to the z score is 0.81

P(x > 4000) = 1 - 0.81 = 0.19

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3 years ago
An aluminum recycling center pays0.08 per pound for cans how much will make receive for 21.5 pounds of cans
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Solve for 'p'
Darina [25.2K]
\left(\dfrac{9a^{-4}}{25}\right)^p=\dfrac3{5a^2}
\left(\dfrac9{25a^4}\right)^p=\dfrac3{5a^2}

One way to find p is to notice that the part on the left hand side within the parentheses can be written as a square:

\dfrac9{25a^4}=\dfrac{3^2}{5^2(a^2)^2}=\left(\dfrac3{5a^2}\right)^2

So you could write

\left(\left(\dfrac3{5a^2}\right)^2\right)^p=\left(\dfrac3{5a^2}\right)^{2p}=\dfrac3{5a^2}

Since these two expressions are equal, and the bases are the same, you know the exponents must be equal, with the exponent on the right hand side being 1. So 2p=1, or p=\dfrac12.
6 0
3 years ago
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