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slava [35]
3 years ago
11

What is 594 divided by 34

Mathematics
2 answers:
3241004551 [841]3 years ago
6 0
17.47 is the answer to that question
dexar [7]3 years ago
3 0
594 divides by 34 equals 17.47
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Pls help...<br><br>solve for x in the following...pls explain <br><br>a)7x+5=3x-1<br>b)5x+12=3x+14​
yKpoI14uk [10]

Answer:

a) x = -1.5

b) x = 1

Step-by-step explanation:

For problem a, you can start by subtracting 3x from both sides to gather all the like terms together:

7x + 5 = 3x - 1

-3x         -3x

4x + 5 = -1

Next, to get the coefficients on one side, you subtract 5 from both sides:

4x + 5 =  -1

    -5      -5

4x = -6

Now, you divide by 4 on both sides to isolate x:

x = -6/4 = -1.5 --- > x = -1.5

For problem b, you start by subtracting 3x from both sides(kinda like problem a):

5x + 12 = 3x + 14

-3x          -3x

2x + 12 = 14

Next, you can subtract 12 from both sides, isolating the "x term".

2x + 12 = 14

       -12  -12

2x = 2

Lastly, you can divide by 2 to get x:

x = 1

7 0
3 years ago
Read 2 more answers
The football team has a total of jerseys. There are ​medium-sized jerseys. What percent of the jerseys are​ medium-sized jerseys
Katena32 [7]

Answer:

70% are medium-sized jerseys.

Step-by-step explanation:

The complete question is:

The football team has a total of 20 jerseys. There are ​14 medium-sized jerseys. What percent of the jerseys are​ medium-sized jerseys? nothing​% are​ medium-sized jerseys.

Solution:

The information provided is:

  • The football team has a total of 20 jerseys.
  • There are ​14 medium-sized jerseys.

Compute the percentage of medium-sized jerseys as follows:

\text{Medium-sized Jerseys}\%=\frac{n(\text{Medium-sized Jerseys})}{N}\times 100

                                     =\frac{14}{20}\times 100\\\\=70\%

Thus, there are 70% medium-sized jerseys.

3 0
2 years ago
Find the surface area of a wooden box full of shape is of a cube and if the age of the box is 4 cm
Sav [38]
All you have to do is multply 4 by all the sides of the cube
4 0
3 years ago
Read 2 more answers
Select the functions that have a value of -1. sin180° cos180° tan180° csc180° sec180° cot180°
kupik [55]

We have to break each degree in terms of 90

A) sin180^\circ=sin(90\times2+0)

Which is in third quadrant, therefore sine is negative hence

sin(90\times2+0)= -sin0 ^\circ = 0


B) cos180^\circ =cos(90\times2+0)

Which is in third quadrant, therefore cosine is negative hence

cos(90\times2+0)= -cos0^\circ  = -1


C) tan180^\circ=tan(90\times2+0)

Which is in third quadrant, therefore tangent is positive hence

tan(90\times2+0)= tan0^\circ  = 0


D) csc180^\circ=csc(90\times2+0)

Which is in third quadrant, therefore cosec is negative hence

cosec(90\times2+0)= -csc0^\circ  =not defined


E)sec180^\circ=sec(90\times2+0)

Which is in third quadrant, therefore secant is negative hence

sec(90\times2+0)= -sec0^\circ  = -1


F) cot180^\circ=cot(90\times2+0)

Which is in third quadrant, therefore tangent is positive hence

cot(90\times2+0)= cot0^\circ = not defined


Hence only cos 180^\circ and

sec180^\circ have value -1

Hope this will help

7 0
3 years ago
6(6x-2)+11x simplified
Helen [10]
47x-12

by step
36x -12 +11
8 0
3 years ago
Read 2 more answers
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