Answer:
The answer is below
Step-by-step explanation:
Don has four different chicken coops on his farm. He gathers eggs from each coop every day to sell at the local farmer's market each week. During one week in the summer, the production levels from the coops were compared. • The number of eggs from coop B can be found by subtracting 10 from coop A's production, and then multiplying this result by two-fifths. • The number of eggs from coop C can be found by adding 3 to coop A's production, multiplying this amount by 3, subtracting 4 from this total, and then dividing the whole result by 4. • The number of eggs from coop D can be found by adding 7 to coop A's production, doubling this amount and then dividing the result by 3. A. Define a variable for the number of eggs produced by coop A. Then write expressions for the number of eggs produced by the other coops. B. If coop A produced 125 eggs, how many did each of the other coops produce? C. If the sum of the number of eggs from coop B and coop C was 24 more than the number from coop D. How many eggs did each coop produce
Solution:
a) Let the number of eggs from coop A be w, number of eggs from coop B be x, number of eggs from coop C be y and number of eggs from coop D be z.
x = 2/5(w - 10) (1)
y = (3(w + 3) - 4)/4
y = (3w + 5) / 4 (2)
z = 2(w + 7)/3 (3)
b) Given that w = 125 eggs:
x = 2/5(125 - 10) = 46 eggs
y = (3(125) + 5) / 4 = 95 eggs
z = 2(125 + 7)/3 = 88 eggs
c) x + y = z + 24.
i.e. 2/5(w - 10) + (3w + 5)/ 4 = 2(w + 7)/3 + 24
multiply through by 60:
24w - 240 + 45w + 75 = 40w + 280 + 1440
69w - 165 = 40w + 1580
29w = 1885
w = 65 eggs
x = 2/5(65 - 10) = 22 eggs
y = (3(65) + 5) / 4 = 50 eggs
z = 2(65 + 7)/3 = 48 eggs
It can go into 48 8 time hope it helps
Answer: 8
Step-by-step explanation: 2x4=8
Your doing 4 x 4 or 2 x2 x 2 x2
He is seven inches taller because twelve minus five is seven.
<h3>
Answer: Choice D) -$22</h3>
You'll lose on average $22 per roll.
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Explanation:
Normally there is a 1/6 chance to land on any given side of a standard die, but your friend has loaded the die in a way to make it have a 40% chance to land on "1" and an equal chance to land on anything else. Since there's a 40% chance to land on "1", this leaves 100% - 40% = 60% for everything else.
Let's define two events
- A = event of landing on "1".
- B = event of landing on anything else (2 through 6).
So far we know that P(A) = 0.40 and P(B) = 0.60; I'm using the decimal form of each percentage.
The net value of event A, which I'll denote as V(A), is -100 since you pay $100 when event A occurs. So we'll write V(A) = -100. Also, we know that V(B) = 30 and this value is positive because you receive $30 if event B occurs.
To recap things so far, we have the following:
- P(A) = 0.40
- P(B) = 0.60
- V(A) = -100
- V(B) = 30
Multiply the corresponding probability and net value items together
- P(A)*V(A) = 0.40*(-100) = -40
- P(B)*V(B) = 0.60*30 = 18
Then add up those products:
-40+18 = -22
This is the expected value, and it represents the average amount of money you earn for each dice roll. So you'll lose on average about $22. Because the expected value is not zero, this means this game is not mathematically fair.
This does not mean that any single die roll you would lose $22; instead it means that if you played the game say 1000 or 10,000 times, then averaging out the wins and losses will get you close to a loss of $22.