Answer:
- 150π ft²
- 10π ft.
Step-by-step explanation:
Area of the sector :
Finding the area given r = 30 ft. and θ = 60° :
⇒ Area = π × (30)² × 60/360
⇒ Area = π × 900/6
⇒ Area = 150π ft²
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Length of the arc :
Finding the arc length given r = 30 ft. and θ = 60° :
⇒ Arc Length = 2 × π × 30 × 60/360
⇒ Arc Length = 60/6 × π
⇒ Arc Length = 10π ft.
1.
(x/2) - 7 = 11
2.
2x + 7 = 27
3.
2x - 5 = 25
Hope this helped!! (:
Answer:
x = 25
Step-by-step explanation:
.20x + .68(120 - x) = .54(120) (Distribute .68 to 120 and -x)
.20x + 81.6 - .68x = .54(120) (multiply .54 and 120)
.20x + 81.6 - .68x = 69.6 ( add .20x and -.68x)
-.48x + 81.6 = 69.6 ( subtract 81.6 on each side)
-.48x = -12 (divide -12 by -.48)
x = 25
Answer:
10)
No. Since the garage is a square, the length and width are the same. And since the formula to find the area of a square is (length times width) l x w , that means that the square root of 121 would be the length and width of the garage. The square root of 121 is 11, concluding that the car that measures 13 feet long is too large.
11)
7. its the square root of 49, which is the closest to 55.
hope this helps!
Answer:
1 is Yes, 2 is No, 3 is No, 4 is No
Step-by-step explanation:
