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Alex17521 [72]
3 years ago
6

2 cars leave phoenix and travel along roads 90 degrees apart. If car 1 leaves 30 minutes earlier than car 2 and averages 42 mph

and if car 2 averages 50 mph how far apart will they be after car 1 has traveled 3.5 hours
Mathematics
2 answers:
ella [17]3 years ago
4 0
<span>Car 1 traveled 3.5 x 42 mph= 147
Car 2 traveled  3 x 50 mph= 150
The distance between them would be </span>√147^2 +150^2
siniylev [52]3 years ago
4 0

got the numbers wrong, sorry.

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Solve the following equation for x.<br> 83x-1 = -73
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You are considering two job offers. The first job pays $8.50 per hour. The second job pays $7.00 per hour plus $0.25 per unit pr
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7

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4 0
3 years ago
Can someone please answer these for me I’m very confused. I need the answers by 20 minutes
Kipish [7]

Answer:

12) y = 2x + 8

13) ( -4, 3)

14) y + 3 = 1(x + 2) ; y = x - 1

Step-by-step explanation:

12) ( -2, 4) and (1, 10)

m=(y2-y1)/(x2-x1)

m= (10-4)/(1+2)

m=6/3

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y - 4 = 2x + 4

y = 2x + 8

13)

y - y1 = m(x - x1)

y - 3 = 2(x +4)

( -4, 3)

14) ( -2, -3) and (4, 3)

m=(y2-y1)/(x2-x1)

m=(3+3)/(4+2)

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y + 3 = 1(x + 2)

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7 0
3 years ago
Help please again. thank chu
Lyrx [107]

Answer:

s = -5

Step-by-step explanation:

solve for s

-50 = 10s

divide both sides by 10

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10s/10 = s

we're left with s = -5

5 0
3 years ago
Read 2 more answers
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