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Kamila [148]
2 years ago
9

PLEASE HELP ASAP!!

Mathematics
2 answers:
Arada [10]2 years ago
6 0
This is like the equivalent to a jar with 4 green balls and 6 white balls, where you are picking 3. (The 4 green balls signify the friends from kindergarten.) 

You want to solve the probability that the first two balls are green and the third is white. 
First draw --> 4 green out of 10 balls --> 4/10 = 2/5 

Second draw --> 3 green out of 9 balls --> 3/9 = 1/3 

Third draw --> 6 white out of 8 balls --> 6/8 = 3/4 


2/5 x 1/3 x 3/4 

= 6/60 

= 1/10 


so the answer is 1/10 (or 10%)
natali 33 [55]2 years ago
3 0

Answer: A 1/10

Step-by-step explanation: Did it on edg

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What is the following product
dangina [55]

Option B is correct.

Step-by-step explanation:

We need to solve: \sqrt[3]{x^2}\sqrt[4]{x^3}

We know that: \sqrt[n]{x}\sqrt[b]{x} =\sqrt[n*b]{x.x}= \sqrt[n*b]{x^2}

Applying the above rule:

\sqrt[3]{x^2}\sqrt[4]{x^3}\\=\sqrt[3*4]{x^2.x^3}\\=\sqrt[12]{x^5}

So, Option B is correct.

Keywords: Solving with Exponents

Learn more about Solving with Exponents at:

  • brainly.com/question/4934417
  • brainly.com/question/13174254
  • brainly.com/question/13174255

#learnwithBrainly

3 0
3 years ago
If h(x) = (f o g)(x) and h(x) = ∛7x+1, find f(x) and g(x)
Mariana [72]
There's more than one way to combine them really
but an obvious one will be

\bf \begin{array}{llll}
h(x)&=&(f\circ g)(x)\\\\
&&\sqrt[3]{7x+1}\\\\
&&\sqrt[3]{g(x)}\leftarrow 
\begin{array}{llll}
f(x)=\sqrt[3]{x }\\\\
g(x)=7x+1
\end{array}
\end{array}\\\\
-----------------------------\\\\
(f\circ g)(x)\iff f[\quad g(x)\quad ]=\sqrt[3]{g(x)}\implies  f[\quad g(x)\quad ]=\sqrt[3]{7x+1}
7 0
3 years ago
What principle will amount to $6000 if invested at 5.5% compounded monthly for 10 years?
Tju [1.3M]

Answer:In 10 years, you will have $10,386.46

Step-by-step explanation:

8 0
2 years ago
Need help will give brainist​
cluponka [151]

Answer:

11. x=15 , 12. x=-16, 13 x is greater than or equal to 15 , 14 x=-3 , 15 x=-3, 16 x=15/2 , 17 x is greater than is equal to -4, 18: x is greater than -11

Step-by-step explanation:

11. 4x+15=75

subtract 15

4x=60

divide

x=15

12. 2x = -32 (subtract 13 from each side)

divide

x=-16

13. multiply each side by

-3/2

x is greater than or equal to 15

14. -3x -18 + 5 = -4

isolate x

-3x=9

x=-3

15. -5x-30 +5=-10

isolate x

-5x = 15

x= -3

16. 2x + 16 = 6x - 14

isolate x

4x = 30

x= 15/2

17 isolate x

x is greater than is equal to -4

18. isolate x

x is greater than -11

4 0
3 years ago
Read 2 more answers
Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137
Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em>78.70^\circ.

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle \triangle ABC with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles \angle A, \angle B, \angle C

As per Law of cosine:

cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}

Putting the values of a,b and c to find out angles \angle A, \angle B, \angle C.

cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ

cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ

cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ

<em>Camera 2nd has to cover the maximum angle</em>, i.e. 78.70^\circ.

6 0
3 years ago
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