Question

Let x be a discrete random variable that possesses a binomial distribution with n=5 and p=0.87. What are the mean and standard deviation of this probability distribution? Round your answers to three decimal places, if required.

Answer 1

Answer:

$Mean = 4.35$

$SD = 0.5655$

Step-by-step explanation:

Given

$n = 5$

$p = 0.87$

Solving (a): Mean

$Mean = np$

$Mean = 5 * 0.87$

$Mean = 4.35$

Solving (b): Standard Deviation (SD)

$SD = np(1 - p)$

$SD = 5 * 0.87(1 - 0.87)$

$SD = 5 * 0.87 * 0.13$

$SD = 0.5655$