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MAXImum [283]
3 years ago
13

Pairs that satisfy function y=2x+1

Mathematics
1 answer:
evablogger [386]3 years ago
8 0

Test a pair from each table by substituting their values into the given equation and solving.

A) y = 2x + 1 .......... 2 = 2(0) + 1 .......... 2 ≠ 1

B) y = 2x + 1 .......... 1 = 2(0) + 1 .......... 1 = 1

C) y = 2x + 1 .......... -1 = 2(0) + 1 .......... -1 ≠ 1

D) y = 2x + 1 .......... -2 = 2(0) + 1 .......... -2 ≠ 1


The only pair that satisfied the equation was from answer choice B. Therefore, B is the correct answer.

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Step-by-step explanation:

\frac{6}{1}  \times  \frac{1}{2}  = 3

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Now add them

\frac{36}{12}   +  \frac{8}{12}  =  \frac{44}{12}  +  \frac{9}{12}  =  \frac{53}{12}

Simplified version is

4 \frac{5}{12}

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