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BaLLatris [955]
3 years ago
5

Name a radius not drawn as part of a diameter

Mathematics
1 answer:
pishuonlain [190]3 years ago
4 0
Wait what do you mean?

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Write a problem that uses a fraction greater than 1.
Gennadij [26K]
3/2+3/2=3 That is a good equation because all of the characters are bigger than one 3/2 is equal to 1.5 and 3 is greater than 1
5 0
3 years ago
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Given f(x)=cos c and g(x)=cot x, what are the domain and range of f(g(x))?
ololo11 [35]

Answer:

Alternative C is the correct answer

Step-by-step explanation:

The first step is to determine the composite function;

f[g(x)]

f[g(x)]=cos[cot(x)]

We then employ a graphing utility to determine the range and the domain of the new function.

The range is the set of y-values for which the function is defined. In this case it is;

[-1,1]

On the other hand, the domain refers to the set of the x-values for which the function is real and defined. In this case; it is the set of real numbers x except x does not equal npi for all integers n.

8 0
3 years ago
Usig the distributive property, an expression equivalent to 34 + 16 is
vampirchik [111]
Pemdas you multiply first meaning you multiply 4 and 4 getting 16 then adding 34 which is the answer to the problem
3 0
3 years ago
Read 2 more answers
I NEED HELP ASP 20 points
leva [86]
Circumference
C = pi d
C = 3.14 x 10
C = 31.4 cm

Area
A = pi r^2
A = 3.14 x 5^2
A = 78.5 cm^2
8 0
3 years ago
state whether the lines represented by the equations y=1/2x-1 and y+4=-1/2(x-2) are paraller, perdendicular, or neither
Brrunno [24]
The easiest way to tell whether lines are parallel, perpendicular, or neither is when they are written in slope-intercept form or y = mx + b. We will begin by putting both of our equations into this format.

The first equation, y =  \frac{1}{2}x - 1 is already in slope intercept form. The slope is 1/2 and the y-intercept is -1.

The second equation requires rearranging.
y + 4 =  -\frac{1}{2}(x - 2) \\ y + 4 = -\frac{1}{2}x + 1 \\ y = - \frac{1}{2} x- 3
From this equation, we can see that the slope is -1/2 and the y-intercept is -3.

When lines are parallel, they have the same slope. This is not the case with these lines because one has slope of 1/2 and the other has slope of -1/2. Since these are not the same our lines are not parallel.

When lines are perpendicular, the slope of one is the negative reciprocal of the other. That is, if one had slope 2, the other would have slope -1/2. This also is not the case in this problem.

Thus, we conclude that the lines are neither parallel nor perpendicular.
8 0
3 years ago
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