Answer: 98.6 - x ≥ 2 or x - 98.6 ≥ 2
Step-by-step explanation:
Since, the normal temperature = 98.6° F
Also, the temperature that differs from normal by at least 2°F is considered unhealthy.
If the temperature is x degree F,
Then, we have two conditions,
Condition 1 : x > 98.6,
The difference between 98.6 and x = x - 98.6
Then the inequality be,
x - 98.6 ≥ 2
Condition 2 : x < 98.6
The difference between 98.6 and x = 98.6 - x
Then the inequality be,
98.6 - x ≥ 2
Difference means subtract, so we use subtraction:
*first we need to make the fractions have the same denominator
1/4 = 3/12
2/3 = 8/12
126(3/12) - 78(8/12)
*since the fraction in the first term is smaller than the second, make it improper
125(15/12) - 78(8/12)
now simply subtract:
125 - 78
= 47
15 - 8
= 7
* this is now (7/12)
now put them back together:
47(7/12)
That's the final answer!
Answer:
it is not possible result is not given so it is not possible
Answer: see proof below
<u>Step-by-step explanation:</u>
Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ
Use the Sum/Difference Identities:
sin(α + β) = sinα · cosβ + cosα · sinβ
cos(α - β) = cosα · cosβ + sinα · sinβ
Use the Unit circle to evaluate: sin45 = cos45 = √2/2
Use the Double Angle Identities: sin2Ф = 2sinФ · cosФ
Use the Pythagorean Identity: cos²Ф + sin²Ф = 1
<u />
<u>Proof LHS → RHS</u>
LHS: 2sin(45 + 2A) · cos(45 - 2A)
Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)
Unit Circle: 2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]
Expand: 2[(1/2)cos²2A + cos2A·sin2A + (1/2)sin²2A]
Distribute: cos²2A + 2cos2A·sin2A + sin²2A
Pythagorean Identity: 1 + 2cos2A·sin2A
Double Angle: 1 + sin4A
LHS = RHS: 1 + sin4A = 1 + sin4A 