Answer:
height = 63 m
Step-by-step explanation:
The shape of the monument is a triangle. The triangle is a right angle triangle. The triangular monument is sitting on a rectangular pedestal that is 7 m high and 16 m long. The longest side of the triangular monument is 65 m . The longest side of a right angle triangle is usually the hypotenuse. The adjacent side of the triangle which is the base of the triangle sitting on the rectangular pedestal is 16 m long.
Since the triangle formed is a right angle triangle, the height of the triangular monument can be gotten using Pythagoras's theorem.
c² = a² + b²
where
c is the hypotenuse side while side a and b is the other sides of the right angle triangle.
65² - 16² = height²
height² = 4225 - 256
height² = 3969
square root both sides
height = √3969
height = 63 m
Answer:
Step-by-step explanation:
A. distribute the X to the X in the parenthesis and you get 2x. Then distribute the X to the -7 in the parenthesis and you get -7x. Combine like terms so that would be 2x-7x and you get -5x.
C. distribute the 6x to the X in the parenthesis and you get 7x. Then distribute the 6x to the 2 in parenthesis and you get 8x. Combine like terms so that would be 7x+8x and you get 15x.
E. Not sure on this one, sorry.
2)
A: 5
B: 9a & a (from a/6)
C: -5 & ÷4
D: -5 & 9a
I haven't done algebra in a year, so don't think my answers are perfect!
definitions:
term: something separated by a sign/symbol (÷, ×, - +) (a/6 are two separate terms, ÷)
constant terms: variables that can be solved.
unlike terms: terms that don't "go" together, you can't subtract 5 from 9a because there's a variable in the way (eyy that rhymes)
like terms: terms that you can add/subtract/multiply/divide to another term
(another answer to c is 9a & a)
Answer:
2/14, 4/28, 5/35, 7/70 or just 2/14
Step-by-step explanation:
Multiply both the numerator and denominator of 1/7 by 2, to get 2/14, or 2:14
And multiply the numerator and denominator of 1/7 by 3, to get 3/21, or 3:21. So 2:14 and 3:21 are two ratios that are equal to 1:7.
